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Lena [83]
3 years ago
5

Given the balanced equation representing a reaction occurring at 101.3 kilopascals and 298 k. 2h2(g) + o2(g) → 2h2o(l) + energy

what is the net amount of energy released when one mole of h2o(l) is produced?
Chemistry
1 answer:
DaniilM [7]3 years ago
8 0
I believe the answer will be 285.8 kJ
The reaction above is for two moles of water; therefore we divide the amount of energy by half. 
The enthalpy of formation of a substance is the energy absorbed or released when one mole of a substance is formed from its constituents elements. For example the enthalpy of formation of water is 285.8 kJ/mol
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What is the concentration (in M) of a 225ml potassium sulfate solution that contains 4.15g of potassium?
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The concentration of solution in M or mol/L can be calculated using the following formula:

C=\frac{n}{V} .... (1)

Here, n is number of moles and V is volume of solution in L.

The molecular formula of potassium sulfate is K_{2}SO_{4} thus, there are 2 moles of potassium in 1 mol of potassium sulfate.

1 mol of potassium will be there in 0.5 mol of potassium sulfate.

Mass of potassium is 4.15 g, molar mass is 39.1 g/mol.

Number of moles can be calculated as follows:

n=\frac{m}{M}

Here, m is mass and M is molar mass

Putting the values,

n=\frac{(4.15 g}{(39.1 g/mol}=0.1061 mol

Thus, number of moles of  K_{2}SO_{4} will be 0.1061\times 0.5=0.053 mol.

The volume of solution is 225 mL, converting this into L,

1 mL=10^{-3}L

Thus,

225 mL=0.225 L

Putting the values in equation (1),

C=\frac{(0.053 mol}{0.225 L}=0.236 M

Therefore, concentration of potassium sulfate solution is 0.236 M.


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emmasim [6.3K]

Answer:

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Explanation:

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1. Potassium hydroxide and sulfuric acid react to produce potassium sulfate salt and water.

2. Potassium hydroxide and phosphoric acid react to produce potassium phosphate and water.

H₃PO₄  + 3KOH  → K₃PO₄ + 3H₂O

3. Phosphoric acid sodium hydroxide react to produce sodium phosphate and water.

H₃PO₄  + 3NaOH   → Na₃PO₄ + 3H₂O

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