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Lena [83]
3 years ago
5

Given the balanced equation representing a reaction occurring at 101.3 kilopascals and 298 k. 2h2(g) + o2(g) → 2h2o(l) + energy

what is the net amount of energy released when one mole of h2o(l) is produced?
Chemistry
1 answer:
DaniilM [7]3 years ago
8 0
I believe the answer will be 285.8 kJ
The reaction above is for two moles of water; therefore we divide the amount of energy by half. 
The enthalpy of formation of a substance is the energy absorbed or released when one mole of a substance is formed from its constituents elements. For example the enthalpy of formation of water is 285.8 kJ/mol
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An unknown compound has the empirical formula CH2O and a molecular mass of 180 amu. What is the molecular formula of the compoun
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The empirical formula gives the simplest ratio of whole numbers of components in the compound. Molecular formula gives the actual composition of elements in the compound.
empirical formula - CH₂O
Mass of one empirical unit = 12 + (1x2) + 16 = 30 a.m.u
We have to next calculate how many empirical units make up the molecular formula. For that we have to divide molecular mass by mass of one empirical unit.
Number of empirical units = 180 a.m.u / 30 = 6
There are 6 empirical units 
Therefore molecular formula = 6 x(CH₂O) = C₆H₁₂O₆
Molecular formula = C₆H₁₂O₆
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Animals breathe oxygen and release carbon dioxide during cellular respiration according to the equation below. How much oxygen i
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Answer:

14.544 g of oxygen is needed to produce 120 grams of carbon dioxide.

Explanation:

Animals take in oxygen and breathe out carbon dioxide during cellular respiration. The reaction for the metabolism of the food in the animal body is:

C_6H_{12}O_6 + O_2 \rightarrow 6CO_2 + 6H_2O + Energy

As can be seen from the reaction stoichiometry that:

<u>6 moles of carbon dioxide gas can be produced from 1 mole of oxygen gas in the process of metabolism of glucose.</u>

Also,

Given :

Mass of carbon dioxide gas = 120 g

Molar mass of carbon dioxide gas = 44 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus, moles of carbon dioxide are:

moles_{CO_2} = \frac{120 g}{44 g/mol}

moles_{CO_2} = 2.7273 mol

As mentioned:

<u>6 moles of carbon dioxide</u> gas can be produced from <u>1 mole of oxygen gas</u> in the process of metabolism of glucose.

<u>1 mole of carbon dioxide</u> gas can be produced from <u>1/6 mole of oxygen gas</u> in the process of metabolism of glucose.

<u>2.7273 mole of carbon dioxide</u> gas can be produced from <u>\frac{1}{6} \times 2.7273 moles of oxygen gas</u> in the process of metabolism of glucose.

Thus, moles of oxygen gas needed = 0.4545 moles

Molar mass of oxygen gas = 32 g/mol

The mass of oxygen gas can be find out by using mole formula as:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Mass\ of\ oxygen\ gas = Moles \times Molar mass}

Mass\ of\ oxygen\ gas = 0.4545 \times 32}

Mass\ of\ oxygen\ gas = 14.544 g

<u>14.544 g of oxygen is needed to produce 120 grams of carbon dioxide.</u>

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