Answer:

Step-by-step explanation:
Answer:
C
Step-by-step explanation:
The perimeter of any shape is the distance around the edge of the shape. It is found by adding the side lengths of each side together.
Add each side length listed for the triangle part.

Multiply the exponent of x by 4giving <span> The answer is </span><span> x^4 evaluates to </span><span> Multiply and 5 </span><span> Multiply and 1 </span><span> The just gets copied along. </span><span> The answer is </span> <span> 5*x^4 evaluates to </span><span> Multiply the exponent of x by 4giving </span><span> The answer is </span><span> x^4 evaluates to </span><span> Multiply and 6 </span><span> Multiply and 1 </span><span> The just gets copied along. </span><span> The answer is </span> <span> 6*x^4 evaluates to </span><span> Multiply the exponent of x by 2giving </span><span> The answer is </span><span> x^2 evaluates to </span><span> Multiply and 3 </span><span> Multiply and 1 </span><span> The just gets copied along. </span><span> The answer is </span> <span> 3*x^2 evaluates to </span><span> 6*x^4-3*x^2 evaluates to </span><span> The answer is </span><span> 6*x^4-3*x^2+7 evaluates to </span><span> Multiply by </span><span> we multiply by each term in term by term. </span> This is the distributive property of multiplication. <span> Multiply and </span><span> Multiply the and </span><span> Multiply and </span><span> Combine the and by adding the exponents, and keeping the x, to get </span><span> The answer is </span> <span> × = </span><span> Multiply and </span><span> Multiply the and </span><span> Multiply and </span><span> Combine the and by adding the exponents, and keeping the x, to get </span><span> The answer is </span> <span> × = </span><span> Multiply and 7 </span><span> Multiply and 1 </span><span> The just gets copied along. </span><span> The answer is </span> <span> × 7 = </span><span> 5*x^4*(6*x^4-3*x^2+7) evaluates to </span><span>The final answer is </span>
Answer:
a) P(x=3)=0.089
b) P(x≥3)=0.938
c) 1.5 arrivals
Step-by-step explanation:
Let t be the time (in hours), then random variable X is the number of people arriving for treatment at an emergency room.
The variable X is modeled by a Poisson process with a rate parameter of λ=6.
The probability of exactly k arrivals in a particular hour can be written as:

a) The probability that exactly 3 arrivals occur during a particular hour is:

b) The probability that <em>at least</em> 3 people arrive during a particular hour is:
![P(x\geq3)=1-[P(x=0)+P(x=1)+P(x=2)]\\\\\\P(0)=6^{0} \cdot e^{-6}/0!=1*0.0025/1=0.002\\\\P(1)=6^{1} \cdot e^{-6}/1!=6*0.0025/1=0.015\\\\P(2)=6^{2} \cdot e^{-6}/2!=36*0.0025/2=0.045\\\\\\P(x\geq3)=1-[0.002+0.015+0.045]=1-0.062=0.938](https://tex.z-dn.net/?f=P%28x%5Cgeq3%29%3D1-%5BP%28x%3D0%29%2BP%28x%3D1%29%2BP%28x%3D2%29%5D%5C%5C%5C%5C%5C%5CP%280%29%3D6%5E%7B0%7D%20%5Ccdot%20e%5E%7B-6%7D%2F0%21%3D1%2A0.0025%2F1%3D0.002%5C%5C%5C%5CP%281%29%3D6%5E%7B1%7D%20%5Ccdot%20e%5E%7B-6%7D%2F1%21%3D6%2A0.0025%2F1%3D0.015%5C%5C%5C%5CP%282%29%3D6%5E%7B2%7D%20%5Ccdot%20e%5E%7B-6%7D%2F2%21%3D36%2A0.0025%2F2%3D0.045%5C%5C%5C%5C%5C%5CP%28x%5Cgeq3%29%3D1-%5B0.002%2B0.015%2B0.045%5D%3D1-0.062%3D0.938)
c) In this case, t=0.25, so we recalculate the parameter as:

The expected value for a Poisson distribution is equal to its parameter λ, so in this case we expect 1.5 arrivals in a period of 15 minutes.

Answer:
185 minutes.
Step-by-step explanation:
It is possible to model an equation for this, such that

where x represents the number of minutes.
Then, you solve for x:
