Question

C++

Answer 1

Answer:

#include <iostream>

#include<iomanip>

using namespace std;

double DrivingCost(double drivenMiles, double milesPerGallon, double dollarsPerGallon)

{

  double dollarCost = 0;

  dollarCost = (dollarsPerGallon * drivenMiles) / milesPerGallon;

  return dollarCost;

}

int main()

{

  double miles = 0;

  double dollars = 0;

  cout << "Enter miles per Gallon   : ";

  cin >> miles;

  cout << "Enter dollars per Gallon: ";

  cin >> dollars;

  cout << fixed << setprecision(2);

  cout << endl;

  cout << "Gas cost for 10 miles : " << DrivingCost(10, miles, dollars) << endl;

  cout << "Gas cost for 50 miles : " <<DrivingCost(50, miles, dollars) << endl;

  cout << "Gas cost for 400 miles: "<<DrivingCost(400, miles, dollars) << endl;

  return 0;

}

Explanation:

• Create a method definition of DrivingCost that accepts  three input double data type parameters drivenMiles,  milesPerGallon, and dollarsPerGallon and returns  the dollar cost to drive those miles .
• Calculate total dollar cost and store in the variable, dollarCost .
• Prompt and read the miles and dollars per gallon  as input from the user .

• Call the DrivingCost function three times  for the output to the gas cost for 10 miles,  50 miles, and 400 miles.

 

Answer 2

Answer:

def driving_cost(driven_miles, miles_per_gallon, dollars_per_gallon):

  gallon_used = driven_miles / miles_per_gallon

  cost = gallon_used * dollars_per_gallon  

  return cost  

miles_per_gallon = float(input(""))

dollars_per_gallon = float(input(""))

cost1 = driving_cost(10, miles_per_gallon, dollars_per_gallon)

cost2 = driving_cost(50, miles_per_gallon, dollars_per_gallon)

cost3 = driving_cost(400, miles_per_gallon, dollars_per_gallon)

print("%.2f" % cost1)

print("%.2f" % cost2)

print("%.2f" % cost3)

Explanation: