Let <em>a</em> be the speed of the plane and <em>w</em> the wind speed.
<em>a</em> - <em>w</em> = (8460 km)/(9 h) = 940 km/h
<em>a</em> + <em>w</em> = (9600 km)/(8 h) = 1200 km/h
Add these speeds together to eliminate <em>w</em> and solve for <em>a</em> :
2<em>a</em> = 1740 km/h
<em>a</em> = 870 km/h
Subtract the first vector from the second to eliminate <em>a</em> and solve for <em>w</em> :
2<em>w</em> = 260 km/h
<em>w</em> = 130 km/h
The formula for a falling object is
v = u +gt
where
u = initial velocity (=0 for a falling object)
g = acceleration due to gravity, 32.2 ft/s²
t = time, s
In terms of distance fallen,
v² = u² + 2gh
where h = distance fallen, ft.
Because h = 23 ft and u = 0, therefore
v² = 2*32.2*23 = 1481.2
v = 38.486 ft/s
Answer: 28.49 ft/s (nearest hundredth)
Answer:
Step-by-step explanation:
We are basically trying to find the hypotenuse of the triangle.
The distance between the x is 2, and the distance between the y is 5, which makes a length and a width.
Pythagrenum theorem: a^2+b^2=c^2
2^2 is 4, 5^2 is 25.
4+25 is 29.
The distance is .
5/6+(-1 1/6) = 5/6-7/6 = -2/6 = -1/3
answer: Put the sum 2 marks to the left of 0 (to place -1/3).
