<h2><u>Question</u><u>:</u><u>-</u></h2>
A fruitseller bought 50kg of the fruits. He sold 30kg of fruits for the cost price of 35kg of fruits and he sold the remaining quantity for the cost Price of 18kg of fruits. calculate his profit or loss percent in the total transaction.
<h2><u>Answer</u><u>:</u><u>-</u></h2>
let the cost price be 50x
→he sells 30kg of fruits on it's CP of 35 kg
→CP of 30kg fruits = 30x
→SP of 35kg fruits = 35x
→remaing fruits are 20kg
→he sells 20kg of fruits on CP of 16kg
→CP of 20kg fruits = 20x
→SP of 20kg fruits = 16x
→total CP is = 50x
→total SP is = (35 + 16) = 51x
→SP > CP (it means profit)
→profit = SP-CP
→ 51-50
→ 1
<h2 /><h2><u>Now,</u></h2>
→ Profit% = gain/CP × 100
→ Profit% = 1/50 × 100
→ 2%
Hence the fruit seller had a profit% of 2%.
Answer:
that will be 2130,1
Step-by-step explanation:
Answer:
a. P(X=50)= 0.36
b. P(X≤75) = 0.9
c. P(X>50)= 0.48
d. P(X<100) = 0.9
Step-by-step explanation:
The given data is
x 25 50 75 100 Total
P(x) 0.16 0.36 0.38 0.10 1.00
Where X is the variable and P(X) = probabililty of that variable.
From the above
a. P(X=50)= 0.36
We add the probabilities of the variable below and equal to 75
b. P(X≤75) = 0.16+ 0.36+ 0.38= 0.9
We find the probability of the variable greater than 50 and add it.
c. P(X>50)= 0.38+0.10= 0.48
It can be calculated in two ways. One is to subtract the probability of 100 from total probability of 1. And the other is to add the probabilities of all the variables less than 100 . Both would give the same answer.
d. P(X<100)= 1- P(X=100)= 1-0.1= 0.9
The answer is 2 because it is quadratic equation
Answer:
The rate at which the distance from the plane to the station is increasing is 331 miles per hour.
Step-by-step explanation:
We can find the rate at which the distance from the plane to the station is increasing by imaging the formation of a right triangle with the following dimensions:
a: is one side of the triangle = altitude of the plane = 3 miles
b: is the other side of the triangle = the distance traveled by the plane when it is 4 miles away from the station and an altitude of 3 miles
h: is the hypotenuse of the triangle = distance between the plane and the station = 4 miles
First, we need to find b:
(1)
Now, to find the rate we need to find the derivative of equation (1) with respect to time:
Since "da/dt" is constant (the altitude of the plane does not change with time), we have:
And knowing that the plane is moving at a speed of 500 mi/h (db/dt):
Therefore, the rate at which the distance from the plane to the station is increasing is 331 miles per hour.
I hope it helps you!
