Answer:
5c + 1.3d - 6.3
Step-by-step explanation:
Hope this helps.
Answer:
4(x+3)
Step-by-step explanation:
Find the smallest number that is divisible by 2, 3, 4, 5, 6 and add 1.
We need the least common multiple of 2, 3, 4, 5, 6.
2 = 2
3 = 3
4 = 2^2
5 = 5
6 = 2 * 3
LCM = product of common and not common prime factors with larger exponent.
LCM = 2^2 * 3 * 5 = 4 * 3 * 5 = 60
To always have a remainder of 1, you need of add 1 to 60.
The number is 61.
Check:
61/2 = 30 remainder 1
61/3 = 20 remainder 1
61/4 = 15 remainder 1
61/5 = 12 remainder 1
61/6 = 10 remainder 1
Answer:
b > 250/9 and w ≥ 0
Step-by-step explanation:
7/9 (b - 27) > 49/81
First, simplify both sides of the inequality:
7/9b - 21 > 49/81
Add 21 to both sides
7/9b - 21 +21 > 49/81 +21
Multiply both sides by 9/7
9/7 x 7/9b > 49/81 x 9/7
b > 1750/81
Simplify
b > 250/9
11w - 8w ≥ 14w
Simplify both sides once again
3w ≥ 14w
Subtract 14w from both sides
3w - 14w ≥ 14w - 14w
-11w ≥ 0
Divide both sides by -11w
w ≥ 0
<span>2(11r + 7) + 1 = 1/4 (88r+60)
</span><span>22r + 14 + 1 = 22r + 15 ---------------------->distributive property
simplify
22r + 15 = 22r + 15
0 = 0
answer: infinite solutions</span>
