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Vsevolod [243]
3 years ago
7

Dan and Camille each have a gift card with a combined balance of $350.00. Dan spent 1/2 of his card balance while Camille spent

1/3 of her card balance. They are both left with an equal amount on their gift cards left. What are they left with.
Mathematics
1 answer:
dezoksy [38]3 years ago
3 0
It should be around $75
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Is 3x + 5 = 3x - 5 one solution or no solution
Ray Of Light [21]

Answer:

one solution

Step-by-step explanation:

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I Reaally Need Help If You Wamt Ill Eve Go Over 100 Points
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(a) y = 2x + 3
(b) (1,5), (3,3); y = 3x + 3      5 = m1 + b, 3 = m3 + b
(c) coincident i believe, because it is not independent or inconsistent
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Xander and Pedro are at an ice cream social.for every scoop of ice cream,Xander uses 1/8 cup of fruit topping.Pedro uses one mor
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Answer: 2 and 3 scoops

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Ms. Gregg spent $14 buying fruit
AnnyKZ [126]

Answer:

Ms. Gregg could buy 4 apples and 6 bananas

Step-by-step explanation:

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8 0
3 years ago
I need help please. Thanks!
Karolina [17]

Answer:

A

Step-by-step explanation:

We are given the function f and its derivative, given by:

f^\prime(x)=x^2-a^2=(x-a)(x+a)

Remember that f(x) is decreasing when f'(x) < 0.

And f(x) is increasing when f'(x) > 0.

Firstly, determining our zeros for f'(x), we see that:

0=(x-a)(x+a)\Rightarrow x=a, -a

Since a is a (non-zero) positive constant, -a is negative.

We can create the following number line:

<-----(-a)-----0-----(a)----->

Next, we will test values to the left of -a by using (-a - 1). So:

f^\prime(-a-1)=(-a-1-a)(-a-1+a)=(-2a-1)(-1)=2a+1

Since a is a positive constant, (2a + 1) will be positive as well.

So, since f'(x) > 0 for x < -a, f(x) increases for all x < -a.

To test values between -a and a, we can use 0. Hence:

f^\prime(0)=(0-a)(0+a)=-a^2

This will always be negative.

So, since f'(x) < 0 for -a < x < a, f(x) decreases for all -a < x < a.

Lasting, we can test all values greater than a by using (a + 1). So:

f^\prime(a+1)=(a+1-a)(a+1+a)=(1)(2a+1)=2a+1

Again, since a > 0, (2a + 1) will always be positive.

So, since f'(x) > 0 for x > a, f(x) increases for all x > a.

The answer choices ask for the domain for which f(x) is decreasing.

f(x) is decreasing for -a < x < a since f'(x) < 0 for -a < x < a.

So, the correct answer is A.

3 0
3 years ago
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