Braden wants to compare the types of ducks in two nearby ponds. He collected two samples using the following criteria. For sampl
2 answers:
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Answer:
90% confidence interval is (43.25, 61.41)
Step-by-step explanation:
Given that,
n = 17
Mean, = 52.33
Standard deviation, = 21.44
∝ = 0.10
Now,
Confidence interval = ±
= 52.33 ± 1.7646 [ 21.44 / √17 ]
= 52.33 ± 9.0791
So,
52.33 + 9.0791 = 61.4091
52.33 - 9.0791 = 43.2509
So,
90% confidence interval is (43.25, 61.41)
Also,
Lower end-point = 43.25
Upper end-point = 61.41