Answer:
2.07 mol O₂
Explanation:
First we need to write down the species present in the chemical equation, using the information given by the exercise:
However this equation <em>is not balanced</em>, so now we<u> balance it</u>:
Now we can use the stoichiometric ratio to <u>calculate the moles of oxygen </u>from the moles of sulfide dioxide:
Answer: We take 20 ml of 1.0 M fruit drink and add 80 ml of water to get 100 ml of 0.2 M solution.
Explanation:
According to the neutralization law,
where,
= molarity of stock solution = 0.2 M
= volume of stock solution = 100 ml
= molarity of resulting solution = 1.0 M
= volume of resulting solution = ?
Now put all the given values in the above law, we get the volume of resulting solution.
Therefore, the volume of 1.0 M required is 20 ml.
We take 20 ml of 1.0 M fruit drink and add 80 ml of water to get 100 ml of 0.2 M solution.