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Karo-lina-s [1.5K]
3 years ago
14

Suppose that, in a given reaction, the enthalpy (H) increases by 10 units, and the disorder (TS) increases by 12 units. By how m

any units did the Gibbs free energy change?When I did the calculation it came out to 2 units but the answer is -2 units. Why is that? Also, is T(delta)S treated as one single unit or separate?
Chemistry
1 answer:
gavmur [86]3 years ago
6 0

Answer:

-2

Explanation:

Gibbs free energy is defined by enthalpy of the system minus the product of the temperature and entropy and represented by the formula below:

G = H - TS where G = Gibbs free energy, H = enthalpy and T =  temperature and S = entropy

change in entropy is defined by the formula below

ΔG = ΔH - Δ(TS)  if the temperature is not constant, but if the temperature is constant then

ΔG = ΔH - TΔS

in according to the question (TS) is treated together.

to the solution

increase in H = 10 units , increase in the product of temperature and entropy = 12 units

ΔG = 10 - 12 = -2

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