Suppose that, in a given reaction, the enthalpy (H) increases by 10 units, and the disorder (TS) increases by 12 units. By how m

Question

3 years ago

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Suppose that, in a given reaction, the enthalpy (H) increases by 10 units, and the disorder (TS) increases by 12 units. By how m

any units did the Gibbs free energy change?When I did the calculation it came out to 2 units but the answer is -2 units. Why is that? Also, is T(delta)S treated as one single unit or separate?

Chemistry

1 answer:

gavmur [86] · Answer 1 · 2022-04-03T23:48:29+03:00

Answer:

-2

Explanation:

Gibbs free energy is defined by enthalpy of the system minus the product of the temperature and entropy and represented by the formula below:

G = H - TS where G = Gibbs free energy, H = enthalpy and T = temperature and S = entropy

change in entropy is defined by the formula below

ΔG = ΔH - Δ(TS) if the temperature is not constant, but if the temperature is constant then

ΔG = ΔH - TΔS

in according to the question (TS) is treated together.

to the solution

increase in H = 10 units , increase in the product of temperature and entropy = 12 units

ΔG = 10 - 12 = -2