Question

The solutions in the two arms of this U-tube are separated by a membrane that is permeable to water and glucose but not to sucrose. Side A is half-filled with a solution of 2 M sucrose and 1 M glucose. Side B is half-filled with 1 M sucrose and 2 M glucose. Initially, the liquid levels on both sides are equal.

Answer 1

Answer:

Intially the glucose concentration is levelled and then the liquid level in side A will rise.

Explanation:

• Initially the liquid ob both sides are in isotonic condition.
• The membrane is permeable to glucose so glucose will diffuse from higher concentration (2 M) to lower concentration (1 M) until the concentration become equal (1.5 M) on both sides.
• Know, the Side A have 2 M sucrose and 1.5 M glucose and  side B have 1 M glucose and 1 M sucrose.
• The side A will become hypertonic and side B will become hypotonic and water will start moving from side B to side A.