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sattari [20]
3 years ago
15

Factor by grouping 2u^3+3u^2-14u-21

Mathematics
2 answers:
nika2105 [10]3 years ago
8 0
(2u³+3u²)-(14u+21)
u²(2u+3)-7(2u+3)
(u²-7)(2u+3)
(u+√7)(u-√7)(2u+3)
mariarad [96]3 years ago
6 0
\bf 2u^3+3u^2-14u-21\implies (2u^3+3u^2)-(14u+21)
\\\\\\
u^2(2u+3)-7(2u+3)\implies \stackrel{\stackrel{common}{factor}}{(2u+3)}(u^2-7)
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3 years ago
Answer quickly please.
jeka57 [31]

Answer:

8.333333

Step-by-step explanation:

 3x+2(4+6x)=133

  3x+8+12x=133                      First I distibuted the 2 too the 4 and 6x

15x+8=133                                 Then I added the x es 3x and 12x

15x+8-8=133-8                         Then I subracted 8 from both sides

15x=125                                    That leaves with this

 15x/15=125/15                          Now I divide 15 from both sides to isolate x

x= 8.33333                                 that is the answer

                             check

                  3x+2(4+6x)=133

                 3*8.333333+2(4+6*8.333333)=133

                  24.999999 +2(4+ 49.999998)=133

                    24.999999+2( 53.999998)=133

                         24.999999+107.999996=133

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4 0
3 years ago
The sum of two numbers is -6. The difference is 16. Find the two numbers.
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Step-by-step explanation:

We can write the following system of equations:

\begin{cases}x+y=6\\x-y=16\\\end{cases}

Adding both equations together, we isolate x and get:

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Plugging x=11 in any of the equations, we can solve for y:

11+y=6,\: y=-5

Verify that the solution pair (11, -5) works \checkmark

Therefore, the two numbers are \fbox{$-5\:\mathrm{and}\: 11$}.

7 0
3 years ago
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solong [7]
4. 8
/ \ / \
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3 years ago
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