Ask question

Ask question

All categories

3 years ago

15

Factor by grouping 2u^3+3u^2-14u-21

2 answers:

nika2105 [10]3 years ago

8 0

(2u³+3u²)-(14u+21)
u²(2u+3)-7(2u+3)
(u²-7)(2u+3)
(u+√7)(u-√7)(2u+3)

mariarad [96]3 years ago

6 0

$\bf 2u^3+3u^2-14u-21\implies (2u^3+3u^2)-(14u+21)
\\\\\\
u^2(2u+3)-7(2u+3)\implies \stackrel{\stackrel{common}{factor}}{(2u+3)}(u^2-7)$

You might be interested in

Does anyone know what the answer is

Natali5045456 [20]

Answer:

cheating in entrance

Step-by-step explanation:

circumference: 14π

area: 49π

8 0

3 years ago

Read 2 more answers

Write the function in function notation. <br> y=7b+8

sesenic [268]

F(b)=7b+8
you just need to change the x variable. make y into f(x) or in this case f(b)

3 0

3 years ago

What are all the exact solutions of -3tan^2(x)+1=0? Give your answer in radians.

goldenfox [79]

$\displaystyle\\
 -3\tan^2x + 1 = 0\\\\
 -3\tan^2x = -1\\\\
\tan^2x = \frac{-1}{-3} \\\\
\tan^2x = \frac{1}{3} ~~~~~ \Big|~\sqrt{~~~} \\\\
\sqrt{\tan^2x} = \sqrt{\frac{1}{3}} \\\\
\tan x = \Big| \frac{1}{ \sqrt{3} } \Big|\\\\
\tan x = \Big| \frac{\sqrt{3}}{ 3 } \Big|\\\\
\tan x = \frac{\sqrt{3}}{ 3 }~~~\Longrightarrow~~x_1= \frac{\pi}{6} + k\pi,~~k \in N \\\\ 
\tan x = -\frac{\sqrt{3}}{ 3 }~~~\Longrightarrow~~x_2= \pi-\frac{\pi}{6} + k\pi = \frac{5\pi}{6} + k\pi,~~k \in N \\\\ 
$

4 0

3 years ago

Read 2 more answers

Which is the graph of f(x) = }(4)*2

zavuch27 [327]

Answer: D

Step-by-step explanation:

Where the x-intercept is 0.25.

5 0

1 year ago

What is the value of the expression 53.5-5? please explain

tatuchka [14]

48.5 is the answer.
Reason- an expression is an equation without an equal sign and this expression is saying 53.5 - 5.

4 0

2 years ago

Read 2 more answers