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sattari [20]
4 years ago
15

Factor by grouping 2u^3+3u^2-14u-21

Mathematics
2 answers:
nika2105 [10]4 years ago
8 0
(2u³+3u²)-(14u+21)
u²(2u+3)-7(2u+3)
(u²-7)(2u+3)
(u+√7)(u-√7)(2u+3)
mariarad [96]4 years ago
6 0
\bf 2u^3+3u^2-14u-21\implies (2u^3+3u^2)-(14u+21)
\\\\\\
u^2(2u+3)-7(2u+3)\implies \stackrel{\stackrel{common}{factor}}{(2u+3)}(u^2-7)
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Select the correct answer.
erica [24]

Answer:

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4 0
3 years ago
Sonny substituted 5 for x in the proportion startfraction 16 over x endfraction = startfraction 48 over 15 endfraction and cross
frez [133]

The cross products of the proportion are equal.

According to the question, Sonny's equation can be written as follows.

16/x = 48/15

Now, the variable x is replaced by the constant 5. So the equation can now be written as follows.

16/5 = 48/15

When two fractions are equal to one another as shown above, the constants are cross multiplied with one another in order to form an equation.

16*15= 48*5

The values of both the products are equal which is 240.

Therefore, because the cross products of the proportion are equal.

Learn more about Proportion on:

brainly.com/question/1496357

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Answer:. .

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3 years ago
HELP ASAP!!! PLEASE CHECK ALL OF THEM!
pochemuha

Answer:

2.

A. (P+h)(x)

2x/x+4 (x-1) + x/x-1 (x+4)

2x^2-1/x^2-4

+

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= 3x^2+3/x^2-4

B. (F-g)(x)

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C. (Fg)(x)

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3.

A. (F+g)(3)

X^2+1 + x-4

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10 -1

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(X^2+1) (x-4)

(-k^2+1) (-k-4)

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= K^2-4k+5 / k-4

Step-by-step explanation:

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How can you use rates to compare the cost of two cereal boxes that are different sizes.
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