Answer:week 3 and week 1
Step-by-step explanation:
In the given question it is given that , AC = 105 yd, BC = 60 yd and angle ACB= 69.3 degree.
We have to find the distance of AB, and for that we use law of cosine, which is
Substituting the values of AC, BC and theta, we will get
We use the equation for repeated trials written below:
Probability = n!/r!(n-r)! * p^(n-r) * q^r
The p is the probability of getting a side A in one toss. Since a counter has only two side, p = 0.5. The q is the probability of not getting side A in one toss, which is also q = 0.5. Now, r is the number of success per n trials. There are 3 tosses so, n=3. The question is getting "at least 1" counter. So, r=1, r=2 and r=3.
Probability for r=1: 3!/1!(3-1)! * (0.5)^(3-1) * (0.5)^1= 0.375
Probability for r=2: 3!/2!(3-2)! * (0.5)^(3-2) * (0.5)^2= 0.375
Probability for r=1: 3!/3!(3-3)! * (0.5)^(3-3) * (0.5)^3= 0.125
Total probability = 0.375 + 0.375 + 0.125 = 0.875
Answer:
3 + x
Step-by-step explanation:
Sum means to add, so you would just add 3 and x (since they haven't given an actual number and only a variable).
In a division problem, ...
... dividend / divisor = quotient
Multiplying both sides of this equation by "divisor", we get ...
... dividend = quotient × divisor . . . . . . . . the desired relationship
The for dividend = 1/8, divisor = 6, and quotient = 1/48, this becomes ...
... 1/8 = 1/48 × 6
... 1/8 = 6/48 = 1/8 . . . . . the given values are consistent
