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-BARSIC- [3]
4 years ago
10

In a science class each student must choose a lab project from a list of 15, write a paper on one of 6 topics, and give a presen

tation about one of 8 subjects. How many ways can students choose to do their assignments?
Mathematics
1 answer:
pishuonlain [190]4 years ago
3 0

Answer:

720 ways

Step-by-step explanation:

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Help plss<br> m/3+2=5 m=?
Salsk061 [2.6K]

Answer:

m = 9

Step-by-step explanation:

Hope this helps. pls let me know if I'm wrong

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3 years ago
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Jabo is standing next to a building. Jabo is 6.25 feet tall, and cast a shadow that 14 feet long. If the building cast a shadow
stich3 [128]

Answer:

64.286ft

Step-by-step explanation:

6.25-->14

x-->144in=12ft im going to asume you meant 144ft or that would be a very small building

14/6.25=2.24ft shadow for 1 real foot

144/2.24=about 64.286ft

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3 years ago
What is 2x+y=1 in slop intercept form?
Mekhanik [1.2K]

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3 years ago
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Solve the equation:<br> - 6n = 2 3/4
Elena-2011 [213]

Answer:

n= 11/24

Step-by-step explanation:

hope it helps

3 0
3 years ago
Find the area of the right triangle △DEF with the points D (0, 0), E (1, 1), and F.
Tems11 [23]

Answer:

The area of the triangle is  \sqrt{3}

Step-by-step explanation:

Given:

Coordinates D (0, 0), E (1, 1)

Angle  ∠DEF = 60°

△DEF is a Right triangle

To Find:

The area of the triangle

Solution:

The area of the triangle is  = \frac{1}{2}(base \times height)

Here the base is Distance between D and E

calculation the distance using the distance formula, we get

DE  = \sqrt{(0-1)^2 + (0-1)^2}

DE =\sqrt{(-1) ^2 + (-1)^2

DE = \sqrt{1+1}

DE = \sqrt{2}

Base = \sqrt{2}

Height is DF

DF =tan(60^{\circ}) \times DE

DF = \sqrt{3} \times DE

DF = \sqrt{3} \times\sqrt{2}

Now, the area of the triangle is

= \frac{1}{2}({\sqrt{2})(\sqrt{3} \times \sqrt{2})

=\frac{1}{2}({\sqrt{2})(\sqrt{3} \sqrt{2})

=\frac{1}{2}(2\sqrt{3} )

=\sqrt{3}

6 0
3 years ago
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