4 years ago

2) What is the specific heat of a metal if 202 J is required to heat 44.0 g of the metal from 22.0°C to

Chemistry

1 answer:

eimsori [14]4 years ago

8 0

Sorry idk the answer i’m just tryna ask my questions... sorry

You might be interested in

Essay about how a drop of water can change states from a gas to a liquid to a solid and back to a gas throught the process of ev

Crank

That will be regarding the water cycle. Write about the importance of the water cycle, each state from evaporation, condensation, precipitation, and run off. How the water cycle affects weather, animals, and the environment.

3 0

3 years ago

Calculate the hydroxide ion concentration [oh-] for human urine (ph = 6.2). notice this is about hydroxide.

igomit [66]

[OH⁻] = 1.6 × 10⁻⁸ mol / dm³

<h3>Explanation</h3>

By definition, $[\text{H}^{+}] = 10^{-\text{pH}}$ , where $[\text{H}^{+}]$ is the concentration of proton in the solution.

pH = 6.2 for this solution. As a result, $[\text{H}^{+} = 10^{-6.2} = 6.31 \times 10^{-7} \; \text{mol} \cdot \text{dm}^{-3}$ .

$[\text{H}^{+}] \cdot [\text{OH}^{-}] = \text{K}_w$ , where $[\text{OH}^{-}]$ the concentration of hydroxide ions and $\text{K}_w$ is the dissociation constant of water.

$\text{K}_w = 10^{-14} \; \text{mol}\cdot \text{dm}^{-3}$ at 0.10 MPa and 25 °C. As a result, $[\text{OH}^{-}] = \text{K}_w / [\text{H}^{+}] = 10^{14} / (6.31 \times 10^{-7}) = 1.6 \times 10^{-8} \; \text{mol}\cdot \text{dm}^{-3}$ .