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Anna71 [15]
4 years ago
6

For each reaction, identify the element that gets reduced and the element that gets oxidized. 2AgCl+Zn⟶2Ag+ZnCl2 Identify the el

ement that gets reduced. chlorine zinc silver Identify the element that gets oxidized. chlorine silver zinc 4NH3+3O2⟶2N2+6H2O Identify the element that gets reduced. hydrogen oxygen nitrogen Identify the element that gets oxidized. nitrogen oxygen hydrogen Fe2O3+2Al⟶Al2O3+2Fe Identify the element that gets reduced. oxygen aluminum iron Identify the element that gets oxidized. aluminum oxygen iron
Chemistry
1 answer:
PolarNik [594]4 years ago
7 0

Answer:

Explanation:

Oxidation no is equal to charge on each atomic ion. If it is increased , element is oxidised and if it is decreased , element is reduced .

2AgCl+Zn⟶2Ag+ZnCl2

Zinc is oxidised , Ag is reduced .

Ag⁺ converts to Ag . ( oxidation number is reduced ) so Ag is reduced.

Zn converts to Zn⁺² ( oxidation number is increased ) so Zn is oxidised .

4NH₃+3O₂⟶2N₂+6H₂O

oxidation number of nitrogen in ammonia is - 3

oxidation no of nitrogen in nitrogen is zero.

Oxidation no of nitrogen is increased so it is oxidised.

oxidation no of oxygen is zero in oxygen and its oxidation no in water is -2 . So oxidation no is reduced so oxidation  is reduced.

Fe₂O₃+2Al⟶Al₂O₃+2Fe

oxidation no of Fe in Fe₂O₃ is + 3 and it is zero in Fe so iron is reduced.

oxidation no of Al in Al is zero and it is +3 in Al₂O₃ so it is oxidised .

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4 years ago
A 25.0 mL sample of a solution of an unknown compound is titrated with a 0.115 M NaOH solution. A buffer region was found around
irinina [24]

Answer:

The unknown compound is a weak acid.

Explanation:

Given that :

a 25 mL sample of a solution of an unknown compound is titrated with a 0.115 M NaOH solution.

A buffer region was found around a pH of 3.5. We know that a pH of 3.5 is a weak acid. So, it is likely to be an organic acid

Let assume the solution of the unknown sample to be CH₃COOH

Now :

25 mL of CH₃COOH reacted with 0.115 M of NaOH

The equation for the reaction will be :

CH₃COOH    +    NaOH -----> CH₃COONa + H₂O

at x mole of      0.115y M of

CH₃COOH       NaOH is present

If NaOH was added in excess;

CH₃COOH    +    NaOH -----> CH₃COONa , NaOH will be lost then CH₃COOH    and CH₃COONa will be present

Therefore;

At equilibrium : Only CH₃COONa will be present but if it is above equilibrium NaOH will be present   because the pH will increase due to the presence of the strong base

8 0
4 years ago
Which of the following solutions has the HIGHEST hydroxide-ion concentration?a) 0.1 M HClb) 0.1 M H2SOc) a buffer solution with
Alexus [3.1K]

Answer:

c) a buffer solution with pH= 5

Explanation:

The equation of hydrolisis of water is:

1x10⁻¹⁴ = [H⁺] [OH⁻]

That means if we know [H⁺] we can find hydroxide-ion concentration and vice versa.

a) HCl 0.1M = [H⁺] = 0.1M;

1x10⁻¹⁴ / [H⁺]

1x10⁻¹⁴/ 0.1M = [OH⁻]

1x10⁻¹³M = [OH⁻] hydroxide- ion concentration.

b) 0.1M H₂SO₄ = 0.2M [H⁺]

1x10⁻¹⁴/ 0.2M = [OH⁻]

5x10⁻¹⁴M = [OH⁻]

c) pH = 5.

[H⁺] = 1x10⁻⁵M

1x10⁻¹⁴/ 1x10⁻⁵M = [OH⁻]

1x10⁻⁹M = [OH⁻]

d) pOH = 12.

[OH⁻] = 1x10⁻¹²M

That means risht answer is:

<h3>c) a buffer solution with pH= 5</h3>

7 0
4 years ago
what is the relationship between the dipole moment and bond moment? explain it with examples ,how it possible for a molecule to
Mariulka [41]

Answer :

Dipole moments occur when there is a separation of charge. Dipole moments occur due to atoms electronegativity, where one atom has the ability to attract electrons towards it giving it a negative charge and the one deficient in electrons acquire a positive charge called as the bond moment.

But if the bond moments are equal and opposite in direction , they cancel each other and thus there is no net dipole moment in the molecule.

For example: In carbon dioxide , both the -C=O bonds are polar but as the molecule is linear and the the magnetic moments are equal and oppposite, they cancel each other and the molecule is non polar.

4 0
3 years ago
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