Answer: Option (a) is the correct answer.
Explanation:
The given data is as follows.
= 4.19
= 1.9
Heat of vaporization () at 1 atm and is 2259 kJ/kg
= 0
Therefore, calculate the enthalpy of water vapor at 1 atm and as follows.
= +
= 0 + 2259 kJ/kg
= 2259 kJ/kg
As the desired temperature is given and effect of pressure is not considered. Hence, enthalpy of liquid water at 10 bar and is calculated as follows.
=
= 334.781 kJ/kg
Hence, enthalpy of water vapor at 10 bar and is calculated as follows.
=
= 2410.81 kJ/kg
Therefore, calculate the latent heat of vaporization at 10 bar and as follows.
=
= 2410.81 kJ/kg - 334.781 kJ/kg
= 2076.029 kJ/kg
or, = 2076 kJ/kg
Thus, we can conclude that at 10 bar and latent heat of vaporization is 2076 kJ/kg.
Answer:
The structure of stearic acid (octadecanoic acid) is shown in the attachment below
Explanation:
Stearic acid is an example of a saturated fatty acid. The structure of stearic acid is shown in the attachment below.
The answer is C because as you add heat, the atoms grow in energy. See the law of conservation of energy states that energy is neither created nor destroyed. This means energy is being added, or converted, in the form of adding heat, increasing the speed of the molecules. This also explains the change from state to state.
Mass of KNO₃ : = 40.643 g
<h3>Further explanation</h3>
Given
28.5 g of K₃PO₄
Required
Mass of KNO₃
Solution
Reaction(Balanced equation) :
2K₃PO₄ + 3 Ca(NO₃)₂ = Ca₃(PO₄)₂ + 6 KNO₃
mol K₃PO₄(MW=212,27 g/mol) :
= mass : MW
= 28.5 : 212,27 g/mol
= 0.134
Mol ratio of K₃PO₄ : KNO₃ = 2 : 6, so mol KNO₃ :
= 6/2 x mol K₃PO₄
= 6/2 x 0.134
= 0.402
Mass of KNO₃ :
= mol x MW KNO₃
= 0.402 x 101,1032 g/mol
= 40.643 g
Answer:
In the absence of urease this will take 950 * 10^6 years to completely hydrolyze
Explanation:
The enzyme urease enhances the rate of urea hydrolysis at pH 8.0 and 20 degrees by a factor of 10^14 . If a given quantity of urease can completely hydrolyze a given quantity of urea in 5 min at 20 degrees and pH 8.0, how long would it take for this amount of urea to be hydrolyzed under the same conditions in the absence of urease?
Step 1: data given
The enzyme urease enhaces the rate of urea hydrolysis at pH = 8.0 of centigrade by a factor of 10^14
Temperature = 20.0 °C
Step 2: Calculate the time it takes to completely hydrolyze without urease
This means when urease is available it takes 5 minutes to completely hydrolyze
When urease is not available it will take 5 *10^14 minutes
5 * 10^14 min = 5 * 10^14 minutes
Since 1 hour = 60 minutes
1 day = 24 hours = 24 *60 minutes = 1440 minutes
It would take : 5 * 10^14 minutes / 1440 minutes = 347222222222.2 days
Since 1 year = 365 days
This will take: 347222222222.2 / 365.25 = 950642634.4 years
This 950 * 10^6 years
In the absence of urease this will take 950 * 10^6 years