Explanation:
Depression in Freezing point
= Kf × i × m
where m is molality , i is Van't Hoff factor, m = molality
Since molality and Kf remain the same
depression in freezing point is proportional to i
i= 2 for CuSO4 ( CuSO4----------> Cu+2 + SO4-2
i=1 for C2h6O
i= 3 for MgCl2 ( MgCl2--------> Mg+2+ 2Cl-)
So the freezing point depression is highest for MgCl2 and lowest for C2H6O
so freezing point of the solution = freezing point of pure solvent- freezing point depression
since MgCl2 has got highest freezing point depression it will have loweest freezing point and C2H6O will have highest freezing point
The hybridization for the Br in BrO4⁻ is 
. So, the correct option is (e).
In chemistry, the idea of combining atomic orbitals to create new hybrid orbitals (with different energies, shapes, etc., than the component atomic orbitals) is known as orbital hybridisation (or hybridization). These new hybrid orbitals are suitable for the pairing of electrons to form chemical bonds in valence bond theory.
Because more directional hybridised orbitals result in higher overlap when creating bonds, stronger bonds are formed, which favours the hybridization of orbitals. When hybridization takes place, this leads to more stable molecules.
One s orbital and three p orbitals combine to form four orbitals, each of which has a 25% s character and a 75% p character. This process is known as hybridization. Anytime an atom is surrounded by four groups of electrons, this kind of hybridization is necessary.
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Potassium is fundamental for neuron activity. If a body does not have enough potassium, then the neuron will struggle to fire because there will not be enough positively charged ions to trigger the firing of the neuron.
The potassium (K+) is maintained at a high level within the neuron at rest, whereas sodium (Na+) is maintained at a high level outside of the cell.
Neurons contain K+ and Na+ leakage channels that allow the two ions to diffuse in favor of a concentration gradient.
Depolarization opens both K+ and Na+ channels in the membrane, thereby these ions can flow out and into the axon, respectively.
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