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3 years ago

A scientist measured an increase in nitrous oxide in the atmosphere. This increase would result in

Chemistry

2 answers:

madreJ [45]3 years ago

7 0

It would result in <span>an increase in the greenhouse effect.</span>

Reil [10]3 years ago

4 0

Answer: Increase in the greenhouse effect

Explanation: Green house effect is a phenomenon which takes place in the earths lower atmosphere making it a place to live.

In this process, the infrared radiations emitted by the sun are being trapped by some of the gases which are known as Greenhouse Gases.

These rays emitted from the sun are very harmful and they could cause hazardous diseases if reached to the earths atmosphere.

Greenhouse Gases are Nitrous Oxide, Carbon dioxide, Methane , water vapor and ozone.

Thus if the concentration of any of the gases will increase in the atmosphere, it will lead to the increase in the greenhouse effect.

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1. A sample of gas has an initial volume of 25 L and an initial pressure of 123.5 kPa. If the pressure changes to

sveta [45]

Answer:

$\large \boxed{\text{17.mL}}$

Explanation:

The temperature and amount of gas are constant, so we can use Boyle’s Law.

$p_{1}V_{1} = p_{2}V_{2}$

Data:

$\begin{array}{rcrrcl}p_{1}& =& \text{123.5 kPa}\qquad & V_{1} &= & \text{25 L} \\p_{2}& =& \text{179.9 kPa}\qquad & V_{2} &= & ?\\\end{array}$

Calculations:

$\begin{array}{rcl}123.5 \times 25 & =& 179.9V_{2}\\3088 & = & 179.9V_{2}\\V_{2} & = &\dfrac{3088}{179.9}\\\\& = &\textbf{17 L}\\\end{array}\\\text{The new volume of the gas is } \large \boxed{\textbf{17 L}}$

6 0

2 years ago

At 25◦C a 4 L sample of H2 exerts a pressure of 5 atm. What pressure would the same sample exert in a 2 L container at 25◦C?

kykrilka [37]

Answer:

10 atm.

Explanation:

Using the combined gas law equation as follows;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question,

P1 = 5 atm

P2 = ?

V1 = 4L

V2 = 2L

T1 = 25°C = 25 + 273 = 298K

T2 = 25°C = 298K

Using P1V1/T1 = P2V2/T2

5 × 4/298 = P2 × 2/298

20/298 = 2P2/298

Cross multiply

298 × 20 = 298 × 2P2

5960 = 596P2

P2 = 5960 ÷ 596

P2 = 10 atm.

4 0

2 years ago

A 250-ml sample of na2so4 is reacted with an excess of bacl2. if 5.28 g baso4 is precipitated, what is the molarity of the na2so

Oksanka [162]

To get the molarity you need to follow this equation
moles of solute
Molarity (M = -----------------------
Liters of solution

But before you apply that equation you need to find the moles of solute and the liters of solution. Follow this equation

Na2SO4 + BaCl2 = BaSO4 + 2 NaCl

Solution

Moles of BaSO4 = 5.28 g
---------------
233.43 g / mol
= 0.0226 moles
Moles of NaSO4 = 0.0226
0.0226 mole
Molarity = -----------------
0.250 L
= 0.0905 mol / L

So the answer is 0.0905 mol / L

3 0

2 years ago

Assume the mass of the star is 60. g. Calculate the density. Use correct number of sig figs.

Stels [109]

It’s a bad idea for a few hours but it’s

7 0

2 years ago

The thin outer layer of Earth, called the crust, contains only 0.50 percent of Earth's total mass and yet is the source of almos

Rzqust [24]

Answer:

The mass of silicon in kilograms in Earth's crust is $7.2729\times 10^{21} kg$ .