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worty [1.4K]
3 years ago
7

A scientist measured an increase in nitrous oxide in the atmosphere. This increase would result in

Chemistry
2 answers:
madreJ [45]3 years ago
7 0
 It would result in <span>an increase in the greenhouse effect.</span>
Reil [10]3 years ago
4 0

Answer: Increase in the greenhouse effect

Explanation:  Green house effect is a phenomenon which takes place in the earths lower atmosphere making it a place to live.

In this process, the infrared radiations emitted by the sun are being trapped by some of the gases which are known as Greenhouse Gases.

These rays emitted from the sun are very harmful and they could cause hazardous diseases if reached to the earths atmosphere.

Greenhouse Gases are Nitrous Oxide, Carbon dioxide, Methane , water vapor and ozone.

Thus if the concentration of any of the gases will increase in the atmosphere, it will lead to the increase in the greenhouse effect.

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Given the balanced equation representing a reaction:
notsponge [240]

Answer:

it is a base because they accept H+ ions

Explanation:

4 0
3 years ago
An element X combines with oxygen to form a compound of formula XO2. If 24.0 grams of element X combines with exactly 16.0 grams
tensa zangetsu [6.8K]

Answer:

atomic mass of X is 48.0 amu

Explanation:

Let y be the atomic mass of X

Molar mass of O_2 is = 2×16 = 32 g / mol

X + O2 -----> XO_2

According to the equation ,

y g of X reacts with 32 g of O_2

24 g of X reacts with Z g of O_2

Z = ( 32×24) / y

But given that 24.0 g of X exactly reacts with 16.0 g of O_2

So Z = 16.0

⇒ (32×24) / y = 16.0

⇒ y = (32×24) / 16

y= 48.0

So atomic mass of X is 48.0 amu

4 0
3 years ago
If a substance conducts heat easily, it is considered to be a
GrogVix [38]
It is considered to be a conductor 
5 0
3 years ago
Read 2 more answers
How many Neutrons are in a ^15N isotope?
Goshia [24]
There are 150 neutrons in 15N
5 0
3 years ago
When 8.00x10^22 molecules of ammonia react with 7.00x10^22 molecules of oxygen according to the chemical equation shown below, h
Pavel [41]
NH₃:

N = 8*10²²
NA = 6.02*10²³

n = N/NA = 8*10²²/6.02*10²³ ≈ 1.33*10⁻¹=0.133mol

O₂:

N=7*10²²
NA = 6.02*10²³

n = N/NA = 7*10²²/6.02*10²³ = 1.16*10⁻¹=0.116mol

4NH₃                   <span>+                        3O</span>₂                      ⇒<span>          2N</span>₂<span> + 6H</span>₂<span>O
</span>4mol                     :                        3mol                   :             2mol
0.133mol             :                        0.116mol           :             0,0665mol
limiting reactant

N₂:

n = 0.0665mol
M = 28g/mol

m = n*M = 0.0665mol*28g/mol = <u>1,862g</u>
6 0
3 years ago
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