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navik [9.2K]
3 years ago
7

How many nitrogen atoms are represented in 2Ca(NO3)2?

Chemistry
1 answer:
arsen [322]3 years ago
4 0

Explanation:

there is 2 nitrogen but if you mean nitrate is 6

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How many elements have an atomic number of 42?<br><br> (Science)
pychu [463]
The top number on elements in the periodic table is the atomic number, so when you look at the periodic table you can see that 42 is Mo (Molybdenum), and this is the only element with that atomic number.

Hope this helped! Please rate 5 starts and hit thanks if it did :)
5 0
3 years ago
Calculate the second volumes. 51.7 L at 27 C and 90.9 KPa to STP
Arturiano [62]

The second volume : 42.2 L

<h3>Further explanation</h3>

Given

51.7 L at 27 C and 90.9 KPa

Required

The second volume

Solution

STP = P₂=1 atm, T₂=273 K

T₁ = 27 + 273 = 300 K

P₁ = 90.9 kPa = 0,897 atm

Use combine gas law :

P₁V₁/T₁ = P₂V₂/T₂

Input the value :

0.897 x 51.7/300 = 1 x V₂/273

V₂= 42.20 L

6 0
3 years ago
Calculate number of particles in 46 g of Na atoms
Harman [31]
The number of particles in 46g of Sodium (Na) atoms are 2.00088735004 mol 
3 0
3 years ago
How many moles are in 18.3 g of CO2?
kaheart [24]

Answer:

0.416moles

Explanation:

Using the formula;

number of moles = mass ÷ molar mass

Molar mass of CO2 = 12 + 16(2)

= 12 + 32

= 44g/mol

According to the information in this question, there are 18.3g of CO2

number of moles (n) = 18.3/44

= 0.4159

= 0.416moles of CO2

7 0
3 years ago
The value of ΔG°′ for the conversion of dihydroxyacetone phosphate to glyceraldehyde-3-phosphate (GAP) is +7.53 kJ/mol . If the
OverLord2011 [107]

Answer:

Concentration of  glyceraldehyde-3-phosphate is 0.0886mM

Explanation:

Get K from the expression exp(ΔG/-RT) = K

Where  

ΔG = Gibbs free energy = 7.53 kJ/ mol = 7.53 * 10^3 J/mol

T = 250C = 273 +25 = 298 K

R = 8.3145 J(mol.K)

K = exp(7530/(-298*8.3145)

K = 4.79*10^-2

NB: K = (conc of products)/(conc of reactants)

From the question

dihydroxyacetone phosphate is the reactant while glyceraldehyde-3-phosphate is the product

4.70*10^-2 = (conc. Of products/1.85mM)

Conc of products = (4.70*10^-2)*1.85

Conc. Of products = 0.0886mM

3 0
3 years ago
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