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nalin [4]
3 years ago
13

Under which conditions can an eclipse occur?

Chemistry
2 answers:
NeX [460]3 years ago
8 0

Answer:

Moon blocks the sun

Explanation:

I hope this is right because i did this question 2 years ago.

dalvyx [7]3 years ago
4 0

Answer:

moon blocks the sun

Explanation:

the moon rotates around the earth and in some cases rotates perfectly to block out the sun and that is called an eclipse

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30. In a common experiment in the general chemistry laboratory, magnesium metal is heated in air to produce MgO. MgO is a white
grigory [225]

Answer: 2Mg + O2 》 2MgO

3Mg + N2 》Mg3N2

Explanation:

6 0
2 years ago
What processes add methane (CH4) to the atmosphere<br>​
tekilochka [14]

Answer:

Cultivated rice paddies

Drilling of natural deposits

Fossil fuel use

Burning of biomass

Landfills

Explanation:

The bulk of the methane released into the atmosphere are as a result of various human activities.

  • Cultivated rice paddies are a known source of methane
  • The drilling of natural deposits and their exploration can release some methane into the atmosphere
  • Burning of fossil fuel and biomass is a source of methane
  • Landfills produces methane as organic materials begins to decay.
8 0
3 years ago
The atmosphere of Venus consists mostly of _____.
lara31 [8.8K]
B. Carbon dioxide bexause it is 96.5%
6 0
3 years ago
Read 2 more answers
The decomposition of dinitrogen pentoxide, N2O5, to NO2 and O2 is a first-order reaction. At 60°C, the rate constant is 2.8 × 10
Ugo [173]

Answer:

The correct option is a.

Explanation:

2N_2O_5\rightarrow 4NO_2 + O_2

125 kPa

125kpa - 2x                            4x    x

Total pressure after reaction = 176 kPa

125 kPa - 2x + 4x + x = 176 kPa

x = 17

125 kpa - 2x = 125 kPa - 2(17) = 91 kPa

Initial pressure of the dinitrogen pentoxide ,(at t=0) =P_o= 125 kPa

Final pressure of the dinitrogen pentoxide, (at t = t) = P = 91 kPa

The rate constant is = k = 2.8\times 10^{-3} min^{-1}

t=\frac{2.303}{k}\log\frac{P_o}{P}

t=\frac{2.303}{2.8\times 10^{-3} min^{-1}}\log\frac{125 kPa}{91 kPa}

t=113.3969 minutes\approx 113 minutes

It will take 113 minutes for the total pressure to reach 176 kPa.

8 0
2 years ago
What is the sign of enthalpy change for (a), an endothermic reaction? (b). an exothermic reaction?
fenix001 [56]

Answer:

The answer is: (a) positive; (b) negative.

Explanation:

The change in enthalpy (ΔH) of a reaction is the amount of energy absorbed or released during a chemical reaction carried out at constant pressure.

a) In an endothermic chemical reaction, heat energy is absorbed by the system from the surrounding. Therefore, the sign of enthalpy change for an endothermic process is positive, ΔH= positive.

b) In an exothermic chemical reaction, heat energy is released by the system into the surrounding. Therefore, the sign of enthalpy change for an exothermic process is negative, ΔH= negative.

8 0
3 years ago
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