3 consecutive positive integers : x, x + 1, x + 2
x^2 = x + 2
x^2 - x - 2 = 0
(x + 1)(x - 2) = 0
x + 1 = 0
x = -1....this is an extraneous solution that does not work
x - 2 = 0
x = 2
check...
square of the first = third
x^2 = x + 2
2^2 = 2 + 2
4 = 4 (correct)
so ur 3 integers are 2,3, and 4
Answer:
A
Step-by-step explanation:
The picture is how you solve it
9514 1404 393
Answer:
72
Step-by-step explanation:
h(4) = 4^3 -2·4 = 64 -8 = 56
g(4) = 3·4 +4 = 16
Then the sum is ...
(h+g)(4) = h(4) + g(4) = 56 +16
(h+g)(4) = 72
Answer:
Discontinuity of function occurs when x = 4 or x = -4
zero of function is when x=0
Step-by-step explanation:
We are given:

Discontinuity of the function occur when the denominator is equal to zero.
So, we need to find the values of x that makes the denominator zero.
The denominator is x^2 - 16
x^2 - 16 =0
x^2 = 16
x = ± 4
So, if the value of x = 4 or value of x=-4 then the function will be discontinuous.
Zero of the function i.e f(x)=0
So, Putting the function equal to zero and finding the value of x

So, zero of function is when x=0
Answer: The second one
Step-by-step explanation: