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Inga [223]
3 years ago
8

A container of water holds 128 fluid ounces. Toya drinks 8 fluid ounces of water every hour. How many fluid ounces are in the co

ntainer after 8 hours
Mathematics
1 answer:
Sidana [21]3 years ago
3 0

Answer: 64 fluid ounces

Step-by-step explanation:

Amount of water in the container = 128 fluid ounces

Amount drank by Toya every hour = 8 fluid ounces

For 8 hours, Toya would have drank:

= 8 × 8 fluid ounces

= 64 fluid ounces

To calculate the amount of fluid ounces

thataree in the container after 8 hours, we then subtract 64 fluid ounces from 128 fluid ounces. This will be:

= 128 fluid ounces - 64 fluid ounces

= 64 fluid ounces

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.5n-9=4n+5 pls i need help
Oksana_A [137]
Hi there,

5n - 9 + 4n + 5
5n - 4n = 5 + 9

Hence,   N = 14

Hope this helps :)
3 0
3 years ago
283838383838382828 + 83838383888282ab
natta225 [31]

2.8392222e+17

Step-by-step explanation:

283838383838382828 + 83838383888282=2.8392222e+17

5 0
3 years ago
A study is conducted to determine if a newly designed text book is more helpful to learning the material than the old edition. T
Oksanka [162]

Answer:

The null and alternative hypotheses are:

H_{0}:\mu=75

H_{a} : \mu>75

Under the null hypothesis, the test statistic is:

t=\frac{\bar{x}-\mu}{\frac{s}{\sqrt{n}} }

Where:

\bar{x} =83 is the sample mean

s=9.8206 is the sample standard deviation

n=10 is the sample size

\therefore t= \frac{83-75}{\frac{9.8206}{\sqrt{10}} }

         =2.58

Now, we can find the right tailed t critical value at 0.01 significance level for df = n-1 = 10 - 1 = 9 using the t distribution table. The t critical value is given below:

t_{critical} =2.821

Since the test statistic is less than the t critical value, we therefore, fail to reject the null hypothesis and conclude that there is not sufficient evidence to support the claim that the people do better with the new edition.

7 0
3 years ago
¿Cuál de los siguientes puntos no pertenece a la función cuadrática f(x) = 1-x^2 ?
dusya [7]

Answer:

<h2>A. (0,1)</h2>

Step-by-step explanation:

The question lacks the e=required option. Find the complete question below with options.

Which of the following points does not belong to the quadratic function

f(x) = 1-x²?

a.(0,1) b.(1,0) c.(-1,0)

Let f(x) = 0

The equation becomes 1-x² = 0

Solving 1-x² = 0 for x;

subtract 1 from both sides;

1-x²-1 = 0-1

-x² = -1

multiply both sides by minus sign

-(-x²) = -(-1)

x² = 1

take square root of both sides;

√x² = ±√1

x = ±1

x = 1 and x = -1

when x = 1

f(x) = y = 1-1²

y = 1-1

y = 0

when x = -1

f(x) = y = 1-(-1)²

y = 1-1

y = 0

Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)

3 0
3 years ago
If sin square theta = 0.75, then cos =
sergeinik [125]

Answer:

\cos\theta=\pm0.5

Step-by-step explanation:

Given:

\sin^2\theta=0.75

To find \cos\theta

Using trigonometric relations for sums and differences of squares of the ratios.

We know:

\sin^2\theta+\cos^2\theta =1

Plugging in  \sin^2\theta=0.75 in the above relation.

0.75+\cos^2\theta =1

Subtracting both sides by 0.75.

0.75+\cos^2\theta-0.75 =1-0.75

\cos^2\theta =0.25

Taking square root both sides.

\sqrt{\cos^2\theta} =\sqrt{0.25}

∴ \cos\theta=\pm0.5  (Answer)

6 0
3 years ago
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