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motikmotik
2 years ago
14

A piggy bank contains $4.45 is dimes and quarters. If the bank contains 25 coins, how many dimes are in the bank?

Mathematics
1 answer:
saul85 [17]2 years ago
4 0

Answer:

12

Step-by-step explanation:

12 dimes is $1.20, so your total for the quarters is $3.25. Since there are 25 coins total and 12 of them are dimes, 25 - 12 = 13, so you have 13 quarters. 13 times its value of 25 cents leaves you with $3.25, fulfilling your needed total.

There likely was an easier way to do this, but I'm unfamiliar with it so I ended up doing this.

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What's the surface area ?
Morgarella [4.7K]

Answer:

ans = 112

Step-by-step explanation:

Hope it will help

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3 0
2 years ago
To make a sauce for the chicken, he will use 0.3 cup of broth per serving of chicken. He has a container with 1.75 cups of broth
xeze [42]

Answer:

Just divide both answer

Step-by-step explanation:

0.3 ÷1.75 or switch it around if it dont work

7 0
3 years ago
What is 0.37 in expanded form using powers of ten.
Leno4ka [110]

Solution

              To   write   0.37   in  expanded  form   using  powers  of  ten

              0.37   can  be   written   as

              0.37  =  0.30  +  0.07

              Since ,

                              0.30    =   3/10

                              0.07    =   7/ 100

              Therefore  ,

                          0.37  =    3/10  +  7/ 100

                                   =    3 x (1 / 10)  +  7 x (1 / 100)

                        Hence , option   C  

           

                 

4 0
3 years ago
Find all the zeros of f(x) help please
Licemer1 [7]

Since f(6)=0, by the remainder theorem this means that <em>x</em> - 6 divides <em>f(x)</em> exactly. This means there are constants <em>a</em>, <em>b</em>, and <em>c</em> such that

\dfrac{f(x)}{x-6} = ax^2 + bx + c

Multiplying both sides by <em>x</em> - 6 gives

f(x) = (x-6)(ax^2+bx+c) \\\\ 2x^3-19x^2+45x-18 = ax^3 + (b-6a)x^2 + (c-6b)x - 6c

Then <em>a</em>, <em>b</em>, <em>c</em> satisfy

\begin{cases}a=2 \\ b-6a=-19 \\ c-6b=45 \\ -6c=-18\end{cases}

and solving this system gives <em>a</em> = 2, <em>b</em> = -7, and <em>c</em> = 3.

So, we have

2x^3-19x^2+45x-18 = (x - 6) (2x^2 - 7x + 3)

The quadratic term can be factored as

2x^2 - 7x + 3 = (2x - 1)(x - 3)

which leaves us with

f(x) = (x-6)(2x-1)(x-3)

so that the zeros of <em>f(x)</em> are 6, 1/2, and 3.

4 0
2 years ago
A.)4<br> B.)10<br> C.)18<br> Which one could be the answer I’m lost.
kirill115 [55]

f(x) = ((x^2) / 3) + x, for f(6)

f(6) = ((6^2) / 3) + 6

Square 6

f(6) = (36 / 3) + 6

Divide 36 by 3

f(6) = 12 + 6

Combine like terms

f(6) = 18

4 0
3 years ago
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