Answer:
Diana's score is better.
Step-by-step explanation:
In Diana case :
Score = 92
Mean score , μ = 71
Standard deviation σ = 15
So,
P( x ≥ 92 ) = 1 - P( x ≤ 92 )
= 1 - P(z ≤ )
= 1 - P( z ≤ )
= 1 - P( z ≤ 1.4 )
= 1 - 0.9192
= 0.0808 = 8.08 %
⇒P( x ≥ 92 ) = 8.08%
∴ we get
Diana score is > 91.92% other students in the class.
In Micheal case :
Score = 688
Mean score , μ = 493
Standard deviation σ = 150
So,
P( x ≥ 688 ) = 1 - P( x ≤ 688 )
= 1 - P(z ≤ )
= 1 - P( z ≤ )
= 1 - P( z ≤ 1.3 )
= 1 - 0.9032
= 0.0968 = 9.68 %
⇒P( x ≥ 688 ) = 9.68%
∴ we get
Micheal score is > 90.32% other students in the class.
From both scores , we can conclude that
Diana's score is better.
