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3 years ago

One sixth of forty-two is seven. How do I write out the equation for that?

Mathematics

1 answer:

sertanlavr [38]3 years ago

6 0

Answer:

Step-by-step explanation:

1/6 * 42 = 7

"of" means multiply

"is" means =

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PLEASE HELP!!!!!!!!!!

AnnZ [28]

Given:

The graph of an exponential function.

To find:

The function in the form of $f(x)=ab^x$ .

Solution:

The general form of an exponential function is

$f(x)=ab^x$ ...(i)

From the given graph it is clear that the function passes through the points (0,4) and (1,7). It means these points will satisfy the function.

For x=0 and f(x)=4,

$4=ab^0$

$4=a(1)$

$4=a$

For x=1 and f(x)=7,

$7=ab^1$

Putting a=4, we get

$7=4(b)$

$\dfrac{7}{4}=b$

Substitute a=4 and $b=\dfrac{7}{4}$ in (i).

$f(x)=4\left(\dfrac{7}{4}\right)^x$

Therefore, the required exponential function is $f(x)=4\left(\dfrac{7}{4}\right)^x$ .

8 0

3 years ago

In ALMN, n = 73 cm, m = 89 cm and Angle M=61º. Find all possible values of Angle N, to the nearest degree.

Dmitrij [34]

Answer:

Step-by-step explanation:

6 0

3 years ago

The box-and-whisker plot shows the ages of employees at a video store. What fraction of the employees are 20 years or older?

BlackZzzverrR [31]

It would be 20/1 as the fraction

7 0

3 years ago

For questions one through two write the ordered pair that is the solution to the system of equations

Oksana_A [137]

Answer:

Ordered pair 1) (-6,) (1.5) (5,4)

Ordered pair 2) (-4) (-1.5) (-2 ,-2)

Step-by-step explanation:

We use the x cross intersection first and last the crossed paths in bold

5 0

3 years ago

Read 2 more answers

Given values: 54, 65, 76, 43, 45, 76, 87 12, 23, 34, 67,65, 78, 45, 34. Given 95% confidence and sigma (population standard devi

Brums [2.3K]

Answer:

Option (D) None of the above.

Step-by-step explanation:

We are given the following data:

54, 65, 76, 43, 45, 76, 87, 12, 23, 34, 67,65, 78, 45, 34

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{804}{15} = 53.6$

Sum of squares of differences = 0.16 + 129.96 + 501.76 + 112.36 + 73.96 + 501.76 + 1115.56 + 1730.56 + 936.36 + 384.16 + 179.56 + 129.96 + 595.36 + 73.96 + 384.16 = 6849.6

$S.D = \sqrt{\frac{6849.6}{15}} = 21.4$

Confidence interval:

$\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

$53.6 \pm 1.96(\frac{21.4}{\sqrt{15}} ) = 53.6 \pm 10.83 = (42.8,64.4)$

8 0

3 years ago