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3 years ago

Circumference of a circle given the radius or diameter? explain why or why not

Physics

1 answer:

djyliett [7]3 years ago

3 0

Circumference of a circle can be calculated if the radius or the diameter is given.

<u>Explanation</u>:

Circumference or the perimeter of a circle can be calculated if the radius or the diameter of the circle is given.
This is calculated by the formula - 2 * pi * r (if radius is given) and pi * d (if diameter is given) where pi = 3.14, r = radius and d = diameter
This calculation is based on the fact that the circumference is three and a little more times that of the radius. Since the diameter is double that of the radius, when the diameter is given formula becomes pi*d.

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Explain how tidal forces are causing Earth to slow down.

dybincka [34]

Answer: The tidal forces exerted by the moon are directly associated with the earth's rotation. Due to the strong gravitational pull of the moon, the tidal bulging appears on both the sides on earth and these are region of high tide, and there is gradual rise and fall of sea level.

Because of these tidal effect, the earth is able to rotate only once in each of the orbital period.

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3 years ago

The electric field strength is 20,000 N/C inside a parallel-platecapacitor with a 1.0 mm spacing. An electron is released fromre

creativ13 [48]

Explanation:

It is given that,

Electric field strength, E = 20,000 N/C

Spacing between parallel-plate capacitor, d = 1 mm = 0.001 m

Initial velocity of electron, u = 0

Let v is the electron’s speed when it reaches the positive plate. The force acting on the electron is :

$F=qE$

Also, $ma=qE$

$a=\dfrac{qE}{m}$

$a=\dfrac{1.6\times 10^{-19}\times 20,000}{9.1\times 10^{-31}}$

$a=3.51\times 10^{15}\ m/s^2$

Using third equation of motion as :

$v^2-u^2=2ad$

$v=\sqrt{2ad}$

$v=\sqrt{2\times 3.51\times 10^{15}\times 0.001}$

v = 2649528.2599 m/s

$v=2.64\times 10^6\ m/s$

So, the velocity of the electron when it reaches the positive plate is $2.64\times 10^6\ m/s$ . Hence, this is the required solution.

4 0

3 years ago

Read 2 more answers

Particles q1 = -53.0 uc, q2 = +105 uc, and

Nimfa-mama [501]

Answer:

$-180.38\ \text{N}$

Explanation:

$q_1=-53\ \mu\text{C}$

$q_2=105\ \mu\text{C}$

$q_3=-88\ \mu\text{C}$

r = Distance between the charges

$r_{12}=0.5\ \text{m}$

$r_{23}=0.95\ \text{m}$

$r_{13}=1.45\ \text{m}$

k = Coulomb constant = $9\times 10^9\ \text{Nm}^2/\text{C}^2$

Net force is given by

$F=F_{12}+F_{13}\\\Rightarrow F=\dfrac{kq_1q_2}{r_{12}^2}+\dfrac{kq_1q_3}{r_{13}^2}\\\Rightarrow F=kq_1(\dfrac{q_2}{r_{12}^2}+\dfrac{q_3}{r_{13}^2})\\\Rightarrow F=9\times 10^9\times (-53\times 10^{-6})(\dfrac{105\times 10^{-6}}{0.5^2}+\dfrac{-88\times 10^{-6}}{1.45^2})\\\Rightarrow F=-180.38\ \text{N}$

The force on the particle $q_1$ is $-180.38\ \text{N}$ .

8 0

3 years ago

Based on your answer,what idea comes in to your mind?

valkas [14]

Answer:

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Explanation:

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3 years ago

If the gradient of an Extension versus Force graph was found to be 5.6, then what is the value of the spring constant? *

worty [1.4K]

Answer:

5.6

Explanation:

F=kx is the formula for spring force. If Extension versus Force was graphed, a linear relation would appear, where the slope is the k value, aka the spring constant.

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3 years ago