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3 years ago

Circumference of a circle given the radius or diameter? explain why or why not

Physics

1 answer:

djyliett [7]3 years ago

3 0

Circumference of a circle can be calculated if the radius or the diameter is given.

<u>Explanation</u>:

Circumference or the perimeter of a circle can be calculated if the radius or the diameter of the circle is given.
This is calculated by the formula - 2 * pi * r (if radius is given) and pi * d (if diameter is given) where pi = 3.14, r = radius and d = diameter
This calculation is based on the fact that the circumference is three and a little more times that of the radius. Since the diameter is double that of the radius, when the diameter is given formula becomes pi*d.

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a child stands with each foot on a different scale. The left scale reads 200N and the right scale reads 150N. what is her mass i

vitfil [10]

Answer:

35.7 kg

Explanation:

We are given that

Left scale reads =200N

Right scale reads=150 N

We have to find the mass in kg.

We know that

Weight of child= Sum of two scales=200+150=350 N

Acceleration due to gravity= $9.8 m/s^2$

We know that

Weight= mg

Using the formula

$350=9.8 m$

$m=\frac{350}{9.8}=35.7 kg$

Hence, the mass of child=35.7 kg

4 0

3 years ago

A ball is dropped from somewhere above a window that is 2.00 m in height. As it falls, it is visible to a person boxing through

Irina18 [472]

Answer:

4.14 m

Explanation:

In the last leg of the journey the ball covers 2 m in 2ms or 0.2 s .

Let in this last leg , u be the initial velocity.

s = ut + 1/2 g t²

2 = .2 u + .5 x 9.8 x .04

u = 9.02 m /s .

Let v be the final velocity in this leg

v² = u² + 2 g s

v² = (9.02)² + 2 x 9.8 x 2

= 81.36 +39.2

v = 10.97 m / s

Now consider the whole height from where the ball dropped . Let it be h.

Initial velocity u = 0

v² = u² +2gh

(10.97 )² = 2 x 9.8 h

h = 6.14 m

Height from window

= 6.14 - 2m

= 4.14 m

5 0

3 years ago

identical springs are placed side-by-side (in parallel), and connected to a large massive block. The stiffness of the 43-spring

allsm [11]

Answer:

The stiffness of one of the individual spring is 390 N/m.

Explanation:

It is given that 43 identical springs are placed side-by-side and connected to a large massive block.

The stiffness of the 43 spring combination is 16770 N/m

We need to find the stiffness of one of the individual springs. Let k is the stiffness of one spring. The effective spring stiffness of this width spring is given by :

$K=N\times k$