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zheka24 [161]
3 years ago
6

Why are lanthanum and actinium at the bottom of the periodic table?

Physics
1 answer:
7nadin3 [17]3 years ago
8 0
The periodic table is organized in a way in which trends with certain things such as ionization energy or atomic radius would "work out". It also have increasing atomic mass.

It's also organized to tell you the electron and proton of each element, least to greatest. (the atomic number) Example: Chlorine has 17 protons and 17 e-
(Left to right)
(Top to bottom)

Lanthanum and actinium play the role of being in the bottom because of their large atomic radius and having many protons/electrons.
They're also in the F block for electron configuration.

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The circuit contains a filament bulb, connected with ........ to a ........
Katyanochek1 [597]

Answer:

The circuit contains a filament bulb, connected with terminal to a terminal.

Explanation:

The base of the electric bulb and the metal tip of the base are the two terminals of the bulb. One is called a positive terminal while the other is called a negative terminal. The filament of the electric bulb is connected to its terminals.

8 0
3 years ago
A cart starts at x = +6.0 m and travels towards the origin with a constant speed of 2.0 m/s. What is it the exact cart position
Ira Lisetskai [31]

Answer:

At the origin (x' = 0 m)

Explanation:

Note: From the question, when the cart travels towards the origin, the magnitude of its exact position reduces with time.

The formula of speed is given as

S = d/t................. Equation 1

Where S = speed of the cart, d = distance covered by the cart over a certain time. t = time taken to cover the distance.

make d the subject of the equation,

d = St ................. Equation 2

Given: S = 2.0 m/s, t = 3.0 s

Substitute into equation 2

d = 2(3)

d = 6 m.

From the above, the cart covered a distance of 6 m in 3 s.

The exact position of the cart = Initial position-distance covered

x' = x-d............ Equation 3

Where x' = exact position of the cart 3 s later, x = initial position of the cart, d = distance covered by the cart in 3.0 s.

Given: x = +6.0 m, d = 6 m.

Substitute into equation 3

x' = +6-6

x' = 0 m.

Hence the cart will be at 0 m (origin) 3 s later

5 0
3 years ago
Mapa conceptual y diferenciar los sistemas de unidades de medida: Internacional e inglés
Zigmanuir [339]

Answer:

dude i have no clue

Explanation:

my bad

8 0
3 years ago
Read 2 more answers
(A) What is the maximum tension possible in a 1.00-millimeter-diameter nylon tennis racket string?
attashe74 [19]

Complete Question

(A) What is the maximum tension possible in a 1.00- millimeter-diameter nylon tennis racket string?

(B) If you want tighter strings, what do you do to prevent breakage: use thinner or thicker strings? Why? What causes strings to break when they are hit by the ball?

The  tensile  strength of the nylon string is  600*10^{6} \  N/m^2

Answer:

A

   T = 471.3 \  N

B

 To prevent breakage the thickness of the string is increased

  String breakage when the racket hit the ball is as a result of the string not being thick enough to withstand the increase in tension

Explanation:

From the question we are told that

     The  diameter is  d =  1.00 \ mm  =  0.001 \  m  

       The  tensile strength of the nylon string is \sigma =  600 *10^{6} \  N/m^2

  Generally the radius is mathematically evaluated as

     r=  \frac{d}{2}

=>    r =  \frac{0.001}{2}

=>     r =  0.0005 \  m

The cross sectional area is mathematically represented as

     A = \pi  r^2

=>   A =  3.142  *  (0.005)^2

=>    A =  7.855*10^{-7}\  m^2

Generally the tensile strength of nylon is mathematically represented as

      \sigma  = \frac{T}{ A }

Where T is the tension on the maximum tension on the string

 So  

           T =  \sigma  *  A

=>          T =  600*10^{6} *  7.855*10^{-7}

=>         T = 471.3 \  N

Form the equation above  we  see that

        T  \  \alpha \  A

So if the tension is  increased to prevent breakage the thickness of the string is increased(i. e the cross-sectional  area )

String breakage when the racket hit the ball is as a result of the string not being thick enough to withstand the increase in tension

8 0
4 years ago
Why are systems in Dynamic Equilibrium stable?
yaroslaw [1]

Answer:

Dynamic Equilibrium are stable because there is an equal rate of transition between reactants and products, or between the forward and the reverse process, in a back and forth manner, such that the net change of the concentration or system is zero, and therefore, there are no excess force factor, tending to create a different outcome

Explanation:

Dynamic equilibrium, in physics and in chemistry, is the equilibrium experienced by a system that undergoes change, where however, both the forward and the reverse effect of the change are taking place.

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3 years ago
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