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shutvik [7]
3 years ago
15

What is the equation of the line of best fit for the following data? Round the slope and y intercept of the line to three decima

l places

Mathematics
2 answers:
ZanzabumX [31]3 years ago
8 0

Answer:

Choice B

Step-by-step explanation:

We can perform a least squares regression model in Ms. Excel to determine the equation of the line of best fit for the data given;

The first step is to enter the data into any two adjacent columns of an excel workbook. Next, click on the Data ribbon followed by the Data Analysis tool pack. We then proceed to select regression from the pop-up window. The final step is to select the y range and the x range of values from our data.

Once we click ok, Excel returns our least squares regression model as shown in the attachment below.

The coefficient of X variable 1 is our slope.

klio [65]3 years ago
7 0

Answer:

b

Step-by-step explanation:

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james went out for a long walk . He walked 3 2/5 of the mile. then he sat down to take rest . After that he walked 5/7 of a mile
kotykmax [81]

Answer:

Altogether James walked 4\frac{4}{35} miles.

Step-by-step explanation:

The question involves mixed fractions. Mixed fractions are first converted into proper fractions and then any operation can be performed on them.

Given

Distance of first walk = 3\frac{2}{5} of a mile

Distance of second walk = 5/7

In order to find how much he walked altogether, we have to find the sum of both fractions.

Total\ distance = 3\frac{2}{5}+\frac{5}{7}\\= \frac{17}{5}+\frac{5}{7}\\=\frac{17*7}{5*7} + \frac{5*5}{7*5}\\=\frac{119}{35} + \frac{25}{35}\\=\frac{119+25}{35}\\=\frac{144}{35}\\=4\frac{4}{35}

Hence,

Altogether James walked 4\frac{4}{35} miles.

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3 years ago
Ludwig takes a job at a large bakery chain. After he is hired, he mentions that he practices a particular religion. The manager
aliya0001 [1]
The correct answer is the civil rights act
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3 years ago
In a state pick 4 lottery​ game, a bettor selects four numbers between 0 and 9 and any selected number can be used more than onc
Anna [14]

Answer:

See explanation below

Step-by-step explanation:

The calculations for this lottery <em>do not involve </em>the combinations rule because <em>the order of the numbers does matter</em>. For example, 1234 and 4321 are different although they have the same digits.

The calculations for this lottery <em>do involve</em> the permutations with replacement rule because any selected number can be used more than once.

By <em>the fundamental rule of counting</em>, there are 10*10*10*10 = 10,000 possible outcomes of the event with a probability 1/10,000 = 0.0001 each outcome.

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3 years ago
If u = 1 + i and v = 1 – i, what is u + v?
murzikaleks [220]

Answer:

2

Step-by-step explanation:

u = 1+i

v = 1-i

u+v =  1+i + 1-i

     = 1+1+i-i

   = 2

3 0
4 years ago
Read 2 more answers
MATH HELP PLZ!!!
RoseWind [281]

Answer:

a)    tan (157.5) = \frac{1-cos 315}{sin315}

b)

            sin (165) =\sqrt{ \frac{1-cos (330) }{2}}

c)

      sin^{2} (157.5) = \frac{1-cos (315) }{2}

d)

  cos 330° = 1- 2 sin² (165°)

       

         

Step-by-step explanation:

<u><em>Step(i):-</em></u>

By using trigonometry formulas

a)

cos2∝  = 2 cos² ∝-1

cos∝ = 2 cos² ∝/2 -1

1+ cos∝ =  2 cos² ∝/2

cos^{2} (\frac{\alpha }{2}) = \frac{1+cos\alpha }{2}

b)

cos2∝  = 1- 2 sin² ∝

cos∝  = 1- 2 sin² ∝/2

sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}

<u><em>Step(i):-</em></u>

Given

              tan\alpha = \frac{sin\alpha }{cos\alpha }

          we know that trigonometry formulas

        sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )

         1- cos∝ =  2 sin² ∝/2

      Given

         tan(\frac{\alpha }{2} ) = \frac{sin(\frac{\alpha }{2} )}{cos(\frac{\alpha }{2}) }

put ∝ = 315

      tan(\frac{315}{2} ) = \frac{sin(\frac{315 }{2} )}{cos(\frac{315 }{2}) }

     multiply with ' 2 sin (∝/2) both numerator and denominator

        tan (\frac{315}{2} )= \frac{2sin^{2}(\frac{315)}{2}  }{2sin(\frac{315}{2} cos(\frac{315}{2}) }

Apply formulas

 sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )

  1- cos∝ =  2 sin² ∝/2

now we get

 tan (157.5) = \frac{1-cos 315}{sin315}

       

b)

          sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}

               put ∝ = 330° above formula

             sin^{2} (\frac{330 }{2}) = \frac{1-cos (330) }{2}

            sin^{2} (165) = \frac{1-cos (330) }{2}

            sin (165) =\sqrt{ \frac{1-cos (330) }{2}}

c )

         sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}

               put ∝ = 315° above formula

             sin^{2} (\frac{315 }{2}) = \frac{1-cos (315) }{2}

            sin^{2} (157.5) = \frac{1-cos (315) }{2}

           

d)

     cos∝  = 1- 2 sin² ∝/2

   put      ∝ = 330°

       cos 330 = 1 - 2sin^{2} (\frac{330}{2} )

      cos 330° = 1- 2 sin² (165°)

3 0
3 years ago
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