Since you OWE,
the best integer is
-20
From V= 4/3*pi*r^3
<span>dV/dt = 4pi(r^2)dr/dt </span>
<span>so when dV/dt=30 and r = 19 </span>
<span>30 = 4pi(361)dr/dt </span>
<span>dr/dt = 30/[4pi(361)] </span>
<span>now in </span>
<span>A = 4pir^2 </span>
<span>dA/dt = 8pi(r)dr/dt </span>
<span>= 8pi(19)*30/[4pi(361)] </span>
<span>= you finish it.</span>
<span>HOPE THIS HELPS.
</span>
Answer: 1 < x < 25
<u>Step-by-step explanation:</u>
The sum of two sides must be GREATER than the third side.
a + b > c a + c > b b + c > a
12 + 13 > x 12 + x > 13 13 + x > 12
25 > x x > 1 x > -1
x < 25 1 < x
Length cannot be negative so disregard x > -1
We are left with 1 < x and x < 25
1 < x < 25
Mmm i don’t know sorry ok
12+6/7n=-25n add 25n and subtract 12 on both sides
25 6/7n=-12 convert to improper fraction
181/7n=-12 multiply both sides by seven to clear the fraction
181n=-84 divide both sides by 181 to get your answer
n= -.46 hope that helps..
