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2 years ago

5,111 ÷ 3 it wont show up on calculator

Mathematics

2 answers:

Lilit [14]2 years ago

5 0

Answer:

1,703.6

Step-by-step explanation:

Mashcka [7]2 years ago

3 0

Answer:

Step-by-step explanation:

In calculator the answer is 1703.66666667

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Suppose that the length of a side of a cube X is uniformly distributed in the interval 9

Nastasia [14]

Answer:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

Step-by-step explanation:

Given

$9 < x < 10$ --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

$v = x^3$

For a uniform distribution, we have:

$x \to U(a,b)$

and

$f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.$

$9 < x < 10$ implies that:

$(a,b) = (9,10)$

So, we have:

$f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Solve

$f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Recall that:

$v = x^3$

Make x the subject

$x = v^\frac{1}{3}$

So, the cumulative density is:

$F(x) = P(x < v^\frac{1}{3})$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$ becomes

$f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.$

The CDF is:

$F(x) = \int\limits^{v^\frac{1}{3}}_9 1\ dx$

Integrate

$F(x) = [v]\limits^{v^\frac{1}{3}}_9$

Expand

$F(x) = v^\frac{1}{3} - 9$

The density function of the volume F(v) is:

$F(v) = F'(x)$

Differentiate F(x) to give:

$F(x) = v^\frac{1}{3} - 9$

$F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}$

$F'(x) = \frac{1}{3}v^{-\frac{2}{3}}$

$F(v) = \frac{1}{3}v^{-\frac{2}{3}}$

So:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

8 0

2 years ago

3. Use the diagram 2 and 3 are ____ angles 1. complementary 2. vertical 3. right 4. supplementary

Vladimir79 [104]

2 and three are supplementary angles .

#4.

The answer is opposite angles .

Hence there is no option

Bisected angles are equal

$\\ \sf\longmapsto 5x=3x+10$

$\\ \sf\longmapsto 5x-3x=10$

$\\ \sf\longmapsto 2x=10$

$\\ \sf\longmapsto x=\dfrac{10}{2}$

$\\ \sf\longmapsto x=5$

Now

m<ABC

$\\ \sf\longmapsto 5x+3x+10$

$\\ \sf\longmapsto 8x+10$

$\\ \sf\longmapsto 8(5)+10$

$\\ \sf\longmapsto 40+10$

$\\ \sf\longmapsto 50$

5 0

2 years ago

Read 2 more answers

What is the quotient of the fractions below?<br> 1/3 divided by 5/8

svetlana [45]

<h3>Answer: 8/15</h3>

Work Shown:

x = (1/3) divided by (5/8)

x = (1/3) * (8/5)

x = (1*8)/(3*5)

x = 8/15

4 0

2 years ago

I need help ASAP

ra1l [238]

Answer:

x =y-3 x=y-3 x=y-3 x=3

2 (y-3) + y= 12 => 3y= 18 => y= 6 => y=6

Step-by-step explanation:

6 0

2 years ago

Explain how to solve the problem below. In your response, you must analyze the given information, discuss a strategy or plan to

alexandr1967 [171]

Answer:

6.1

please give me brainliest!!

Step-by-step explanation:

Imagine right triangle with first leg to be the Chad length and second leg to be the Chad's shadow. Second leg has length 14.3 ft and since the straight-line distance from the top of Chad’s head to the end of the shadow creates a 23° angle with the ground, you could consider the trigonmetric function

tan23 = chad's length/chads shadow length

tan23 = chad's length/14.3

chad's length = 14.3 * tan23 = 6.1

6 0

2 years ago