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3 years ago

Use ΔDEF, shown below, to answer the question that follows

Mathematics

1 answer:

AVprozaik [17]3 years ago

8 0

Using sine rule, 55 / sin 90 = x / sin(90 - 49)
55 / 1 = x / sin 41
x = 55 sin 41 = 36.08

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A || b what’s the value of X?

Anna007 [38]

<h3><u>Answer:</u></h3>

The value of x is 17.

<h3><u>Step-by-step explanation:</u></h3>

<u>We know that the lines are parallel because it is given that:</u>

a ∥ b

<u>Now, let's form an equation.</u>

=> 2x + 5 + 8x + 5 = 180

<u>Let's solve!</u>

=> 10x + 10 = 180
=> 10x = 170
=> x = 17

Hence, the value of x is 17.

$BrainiacUser1357$

4 0

2 years ago

PLEASE HELP:

wlad13 [49]

76/2=38 so half her mothers age is 38. And since Moira is 3 less than the half of her mothers age, Moira is: 38-3=35

4 0

3 years ago

PLEASE HELP!!!!!!!!!!!!!!!!!!!!

Semmy [17]

The answer would be 167 I believe

7 0

3 years ago

A florist owns two flower shops. The profit for the month of June at the first location can be represented by the function p(x)=

Dmitrij [34]

Answer:

$r(x) = 38x + 375$

Step-by-step explanation:

Given:

Profit in the month of June from first location is $p(x)=202+21x$

Profit in the month of June from second location is $q(x)=17x+173$

Now, total profit from the two locations can be obtained by adding the profits from each of the two locations.

Now, adding both the profits, we get:

$r(x)=p(x)+q(x)$

Plug in the given values and simplify. This gives,

$r(x)=202+21x+17x+173$

Now, we need to combine the like terms using commutative property.

Therefore, rearranging the terms, we get:

$r(x)=21x+17x+202+173\\\\r(x)=38x+375$

Therefore, the correct option is the first option.

5 0

3 years ago

The graph of an inverse trigonometric function passes through the point (1, pi/2). Which of the following could be the equation

rodikova [14]

Answer: C) $y=sin^-1 x$

Step-by-step explanation:

Since, the graph of an inverse trigonometric function will pass through the point $(1,\frac{\pi}{2})$ ,

If this point satisfies the function,

For the function $y=cos^{-1} x$

If x = 1

$y=cos^{-1}1=0$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=cos^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=cot^{-1}x$

If x = 1

$y=cot^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cot^{-1}x$ ,

⇒ The graph of $y=cot^{-1}x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=sin^{-1} x$

If x = 1

$y=sin^{-1}1=\frac{\pi}{2}$

Thus, $(1,\frac{\pi}{2})$ is satisfying function $y=sin^{-1} x$ ,

⇒ The graph of $y=sin^{-1} x$ is passing through the point $(1,\frac{\pi}{2})$ .

For the function $y=tan^{-1}x$

If x = 1

$y=tan^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=tan^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$ .

Hence, Option C is correct.

3 0

3 years ago