The equation of a circle centred at point (m,n) and radius r is given by
<span>(x-m)² + (y-n)² = r²
</span>-------------------------------------------------------------
Centre = (4,3)
radius = 5
Equation:
(x - 4)² + (y - 3)² = 5²
⇒ x² - 8x + 16 + y² - 6y + 9 = 25
⇒ x² + y² - 8x - 6y + 25 = 25
⇒ x² + y² - 8x - 6y = 0
The equation of the circle is x² + y² - 8x - 6y = 0
Hope it helps!
Answer:
36π
Step-by-step explanation:
d= 6 in
r= d/2=6/2= 3 in
volume of sphere= 4/3πr^3
=4/3 ×π×3^3
=36π in^3
Answer:
Solution,
Let,(x1,y1)=(-4,-3)
(x2,y2)=(3,5)
Using distance formula,
AB=√(x2-x1)²+(y2-y1)²
=√(3+4)²+(5+3)²
=√49+64
=√113 units.
Step-by-step explanation:
If x approach infinity then (x² + 1)/(2x² +1) = 1/2 then lim as x approach infinity
lim y = arccos 1/2 = 1.047
