Answer:
324
Step-by-step explanation:
Simplify it
Answer: I will answer questions answer to question question answer questions about the answer question answer questions and questions about questions answer questions questions about questions or questions about questions answer questions about the questions answer question
I have a little bit of a little bit more about to get a new one and but I’m going back to the office now and I’m not sure if you want Step-by-step explanation:
Answer:
i think 120, im not quite sure, im not the best at this
Step-by-step explanation:
For polar form you need to find the modulus (length of the vector) and the argument (angle of the vector) and present in form rcis(Arg) or re^Argi
start with the modulus r=sqrt(a^2 +b^2)
=sqrt(-2^2 +2^2)
= sqrt(4+4)
=sqrt(8)
=2sqrt(2)
next the argument, firstly arg=tan(b/a)
= tan(2/2)
=tan(1)
=pi/4 . (exact values table)
Now consider the quadrant the complex number is in, as it is (-2,2) it is in the second quadrant and as such your Arg value is:
Arg=pi-arg
= pi-pi/4
= 3pi/4
add it all together and your complex number in polar form is:
2sqrt2cis(3pi/4)
note: cis is short hand for cos(x)+isin(x), it is possible your tutor would rather you use the complex exponential form which is simply re^Argi and your answer would look like:
2sqrt2e^(3pi/4)i
Also notice the difference between arg and Arg as this often slips students up and always present Arg in prinicple argument form ie -pi<Arg<pi
Hopefully this has been clear enough and good luck
In a quadratic function you square x so I'd assume that's what they want.
That means the values of f(x) would be:
9
1
1
9
25
