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3 years ago

A county fair charges $5 for tickets and $2 for each ride. What is the y-intercept in this scenario?

Mathematics

1 answer:

Anastasy [175]3 years ago

5 0

The y-intercept in this scenario is y= 5x+2

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Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

ANSWER:

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

SOLUTION:

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

2 years ago

Solve the following system. x-y=2. 3x+z=11. y-2z=-3

dexar [7]

For the 1st one we need to solve x. x-y=2 step1: x-y+y=2+y answer: x=y+2

5 0

2 years ago

a parking meter accepts only 20p coins or 50p coins.On one day, 39 coins were collected with a total value of $11.40. find how m

Snowcat [4.5K]

Answer:

x + Y = 39 or x = 39-y

20x + 50y = 1.40

20 (39 - y) + 50y = 11.40

7.80 - 20y + 50y = 11.40

30y = 11.40 - 7.80

30y = 3.60

y = 3.60/30

y = 12 50p coins were collected.

x = 39 - 12 = 27 20p coins were collected.

Proof:

20*27 + 50*12 = 11.40

5.40 + 6 = 11.40

11.40 = 11.40

I hope it helps.

6 0

2 years ago

Read 2 more answers

3a. Write an equation in slope-intercept form of a line that passes through (2,1) and (6,-5).

eimsori [14]

Answer:

$y =- 3/2x + 4$

Step-by-step explanation:

$(2,1) and (6,-5).\\x_1 = 2\\x_2 = 6\\y_1 =1\\y_2 =-5\\\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}\\ \\\frac{y-1}{x-2} = \frac{-5-1}{6-2}\\\\\frac{y-1}{x-2} = \frac{-6}{4} \\Cross-Multiply\\4(y-1) = -6(x-2)\\4y-4=-6x+12\\4y =-6x+12+4\\4y = -6x+16\\Divide- through-by ; 4\\\frac{4y = -6x+16}{4} \\\\y = -\frac{3}{2} x +4$

5 0

3 years ago

How do you do conditional statements

Goshia [24]

Example P: I do my homework
P: I get my allowance

8 0

3 years ago