6x+3y=33..........(1)
4x+y=15
y=15-4x.........(2)
substitute value of y from (2) in (1)
6x+3(15-4x)=33
distribute 3 over the bracket
6x+45-12x =33
-6x=33-45
-6x=-12
x=2
plugging this value of x in equation 2 we get
15-4x=y
15-4(2)=y
y=15-8
y=7
Answer is x=2 and y=7
Answer:
d
Step-by-step explanation:
the last one of the four
11
If you replace the x with 11, the new equation would be 10+5(11)=65. First, multiply 5 and 11, your answer would be 55, then add the ten, you would get 65. Which makes the equation true, because 65=65.
I hope this helps
If you have any questions on my answer please feel free to ask :)