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const2013 [10]
3 years ago
14

Which methods could you use to calculate the y-coordinate of the midpoint of a vertical line segment with endpoints at (0,0) and

(0,15)
Mathematics
1 answer:
konstantin123 [22]3 years ago
5 0

The mid point of a line with end points (x₁,y₁) and (x₂,y₂) is given by the formula

[\frac{x1+x2}{2} , \frac{y1+y2}{2}]

Here we only need the y coordinate hence lets calculate the y coordinate alone

=\frac{0+15}{2}

=7.5


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3 years ago
What is the GCF of 20, 36 and 48
nlexa [21]
20= 1,2,4,5,10,20
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3 years ago
If y varies directly as​ x, and y=8 when x=3​, find y when x=15.
Crank

Answer:

y=40

Step-by-step explanation:

The formula for Direct Variation is y=kx or k=y/x. In this case I would use k=y/x. If you're y is 8 and x is 3, this means that K=8/3. Using this, we know that X=15. We have to find a Y value so that the fraction with an x of 15 simplified is 8/3. To do this you would write 8/3 and y/15. Now cross multiply to get 3y=120. Divide by 3 to get y=40. View my attachment for the work!

8 0
3 years ago
Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li
Sophie [7]
Consider the closed region V bounded simultaneously by the paraboloid and plane, jointly denoted S. By the divergence theorem,

\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV

And since we have

\nabla\cdot\mathbf f(x,y,z)=1

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV
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=\dfrac\pi2

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by D, we have

\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS

Parameterize D by

\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k
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Vlad [161]

Answer:

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7 0
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