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lisabon 2012 [21]

2 years ago

15

What is 5000000000 x 6600000000?

1 answer:

otez555 [7]2 years ago

7 0

There you go
.........................

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The endpoint of a line segment is (-9, 7). The midpoint of the segment is (10, -3). Find the other endpoint. *show work*

slavikrds [6]

First we will find the x coordinate.

x1+x2 / 2 = the x coordinate of the midpoint.

-9 + x2 / 2 = 10
x2/2 -4.5 = 10
x2/2 = 14.5
x2 = 29

Now the y coordinate:

y1+y2 /2 = y coordinate of the midpoint

7 + y2 / 2 = -3
y2/2 + 3.5 = -3
y2/2 = -6.5
y2 = -13

So the other endpoint is (29,-13)

I hope i am right :)

8 0

2 years ago

Dan counted all the coins in his bank, and he had 72 quarters. can he exchange the quarters for an even amount of dollar bills?

Vladimir [108]

There are 4 quarters in a dollar. If you divide 72 by 4 and you do not get a remainder then he can.

8 0

3 years ago

What is 2/9 divided by negative 6/5

Lerok [7]

The answer to your question is 5/27

4 0

2 years ago

Read 2 more answers

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

6 0

2 years ago

If f (x)=3^5-x + 6, what is the value of f (5), to the nearest tenth?

Amiraneli [1.4K]

Answer:

240

Step-by-step explanation:

3^5 - 5 + 6

243 - 5 = 238+6= 244

240?

8 0

3 years ago