The length of side of triangle is 5 units and length of side of pentagon is **1.5 units.
**

<u>**SOLUTION:**</u>

Given, An equilateral triangle has sides of length units.

Then, perimeter of the triangle will be

A regular pentagon (5 sides) has sides of units.

Then, perimeter of the pentagon will be

We have to find the dimensions of each shape
. Now, the perimeter of the triangle is twice the perimeter of the pentagon,

So,

Then, length of side of triangle

Length of side of pentagon

We have to neglect, negative sign as lengths can’t be negative. Even if we change the sign above all conditions are satisfied.

He swapped the 6 and the 5 in the beginning of the number

Well when ever you're doing order of operations you always use please excuse my dear aunt sally please means parentheses ALWAYS GO FIRST Excuse means experience which if there's no parentheses exponents go first to my name is multiplication after parentheses multiplication always go first if there's no parentheses dear means division after multiplication comes division on means addition but pretty much after the multiplication parentheses and the division you complete the rest of the problem using the left to right method now the answer to this problem is

**Answer:**

7.5s

1.6666 repeating or 1.67 m/s²

**Step-by-step explanation:**

the equation you have to use is Vfinal=Vstart+acceleration•time

(I'm gonna simplify to Vf=Vs+at)

so you gotta rework it for the two equations

for the first equation you need time so take Vf=Vs+at and subtract Vs on both sides to get Vf–Vs=at

then divide acceleration on both sides to get t=(Vf–Vs)/a

for the second problem equation need the equation a=(Vf–Vs)/t (just divide time on both sides instead of acceleration)

so you the plug in

(I don't put the units in to the problem unless needed)

1. t=(Vf–Vs)/a to t=(0–30)/-4.0

t= -30/-4.0

t=7.5 seconds

2. a=(Vf–Vs)/t to a=(10–0)/6.0

a= 10/6.0

a= 1.67m/s²

(I'm assuming the that for number two they started at rest so it would be 0m/s for velocity start)