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3 years ago

Which graph below shows the solutions for the linear inequality y<1/4x-3

Mathematics

2 answers:

Luda [366]3 years ago

4 0

The answer is GRAPH C.

Oxana [17]3 years ago

4 0

y< 1/4x - 3

Lets y = 1/4 x - 3 and find 2 coordinate points

y intercept : x = 0, y = -3. so It's (0, -3)

when x = 4, y = 1/4 (4) - 3 = 1 - 3 = - 2 , so it's (4, - 2)

Now you have two coordinate points (0, -3) and (4, - 2)

The inequality symbol is less than (<), the line is dotted and also shade the side "under" the line.

Answer is C. Graph C

Bottom left

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Answer:

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3 years ago

What is the value expression 8+24 divided by (2 times 6) - 4

Sphinxa [80]

Answer:

Step-by-step explanation:

Given mixed operations there is a particular order that must be followed.

Using the order set out in the acronym PEMDAS

P - Parenthesis ( brackets ), E- Exponents ( powers ), M - Multiplication, D - Division, A- Addition, S - Subtraction

8 + 24 ÷ (2 × 6) - 4

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3 years ago

Question 16 of 40

Sunny_sXe [5.5K]

The answer b your welcome so much

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3 years ago

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon

fiasKO [112]

Answer:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.

This means that $n = 603, \pi = \frac{142}{603} = 0.2355$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a p-value of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694$

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

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2 years ago