Answer:
60
skip count to find lest common denominator quickly
Answer:
A.(170+30)-41
Step-by-step explanation:
(170+30)-41=170+(30-41)
200-41=170+(-11)
159=170-11
159=159
Answer:
There are 15 letters, but if the two A's must always be together, that's the same as if they're just one letter, so our "base count" is 14! ; note that this way of counting means that we also don't need to worry about compensating for "double counting" identical permutations due to transposition of those A's, because we don't "count" both transpositions. However, that counting does "double count" equivalent permutations due to having two O's, two N's, and two T's, so we do need to compensate for that. Therefore the final answer is 14!/(23)=10,897,286,400
We know that Step 1 is correct, because it is just a restatement of the equation. Therefore, we can eliminate Step 1:
2(5y – 2) = 12 + 6y
In Step 2, the student tried using the Distributive Property. The Distributive Property can be written as one of the two following formulas:
a(b + c) = ab + ac
a(b – c) = ab – ac
In this case, we'll use the second formula. Substitute any known values into the equation above and simplify:
2(5y – 2) = 2(5y) – 2(2)
2(5y – 2) = 10y – 4
In Step 2, the student calculated 2(5y – 2) to equal 7y – 4. However, we have just proven that 2(5y – 2) is equal to 10y – 4.
The student first made an error in Step 2, and the correct step is:
Step 2: 10y – 4 = 12 + 6y
I hope this helps!
