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Dima020 [189]
3 years ago
12

Which audio format is used to create chiptunes?

Computers and Technology
2 answers:
Scilla [17]3 years ago
5 0
Chiptune, also known as chip music or 8-bit music, is synthesized electronic music which is made for programmable sound generator suns chops used in vintage computers,consoles , and arcade machines.
rodikova [14]3 years ago
3 0
I would look at this: https://en.m.wikipedia.org/wiki/Chiptune
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Which of the following are vector graphic file formats? Choose all that apply.
blondinia [14]

There are different kinds of files. The option that is a vector graphic file formats is SVG.

<h3>What are vector files?</h3>

Vector files are known to be a type of images that are created by using mathematical formulas that stands as points on a grid.

The SVG  is known as Scalable Vector Graphics file and it is known to be a  vector image file format as it make use of geometric forms such as points, lines, etc.

Learn more about vector graphic file from

brainly.com/question/26960102

3 0
2 years ago
PLEASE HURRY
creativ13 [48]
I'm pretty sure it's C) or D) because it seems those make the most sense because providing excitement does not matter if that is not their point, repeating a previous point is practically useless because that point has already been said.
5 0
3 years ago
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6. How can you encrypt an entire drive, including files and folders belonging to other users? a. EFS b. User Account Control c.
matrenka [14]

Answer:

A.

Explanation:

Encrypting File System (EFS) is a file system which enables you to encrypt files, thus making them unviewable by any account but your own.

6 0
3 years ago
Create an application containing an array that stores eight integers. The application should call five methods that in turn (1)
Butoxors [25]

Answer:

package b4;

public class ArrayMethodDemo {

public static void main(String[] args) {

 // Create an array to store 8 random integers.

 int[] integernumbers = { 3, 4, 6, 9, 5, 6, 7, 2 };

 // Call the display method to show the elements in the array.

 display(integernumbers);

 // Call the method to display the elements in reverse order.

 displayReverse(integernumbers);

 // Call the method to find the sum of the elements.

 sum(integernumbers);

 // Call the method to display all elements less than a limiting value, say 5.

 lessThan(integernumbers, 5);

 // Call the method to display all elements greater than the average of the array

 // elements.

 higherThan(integernumbers);

}

// Method to display the elements in the array.

// The method receives only a single argument which is the array.

// Loop through the array and at every cycle, print out each element

public static void display(int[] arr) {

 System.out.print("All integers in the array : ");

 for (int i = 0; i < arr.length; i++) {

  System.out.print(arr[i] + " ");

 }

 System.out.println();

}

// Method to display the elements in the array in reverse order

// The method receives only a single parameter which is the array

// Loop through the array starting at the last index

// At every cycle, print out the elements in the array

public static void displayReverse(int[] arr) {

 System.out.print("All integers in the array in reverse : ");

 for (int i = arr.length - 1; i >= 0; i--) {

  System.out.print(arr[i] + " ");

 }

 System.out.println();

}

// Method to print out the sum of the elements in the array.

// The method receives only a single parameter which is the array.

// Declare a variable called sum to hold the sum of the elements

// Initialize sum to zero

// Loop through the array and cumulatively add each element to sum

// Print out the sum at the end of the loop

public static void sum(int[] arr) {

 int sum = 0;

 for (int i = 0; i < arr.length; i++) {

  sum += arr[i];

 }

 System.out.println("The sum of the integers in the array is " + sum);

}

// Method to print all values in the array that are less than a limiting

// argument.

// The method has two parameters - the array and the limiting argument.

// Loop through the array and at every cycle,

// check if the current array element is less than the limiting argument.

// If it is, print it out. Else continue

public static void lessThan(int[] arr, int limitingargument) {

 System.out.print("All values less than the limiting argument (" + limitingargument + ") are: ");

 for (int i = 0; i < arr.length; i++) {

  if (arr[i] < limitingargument) {

   System.out.print(arr[i] + " ");

  }

 }

 System.out.println();

}

// Method to print all values in the array that are higher than the average of

// the array.

// The method has one parameter - the array.

// First, calculate the average of the array elements.

// Loop through the array and at every cycle,

// check if the current array element is greater than the average.

// If it is, print it out. Else continue

public static void higherThan(int[] arr) {

 int sum = 0;

 for (int i = 0; i < arr.length; i++) {

  sum += arr[i];

 }

 double average = sum / arr.length;

 System.out.print("All values higher than the calculate average (" + average + ") is ");

 for (int i = 0; i < arr.length; i++) {

  if (arr[i] > average) {

   System.out.print(arr[i] + " ");

  }

 }

 System.out.println();

}

}

Explanation:

The program has been written in Java.

Please go through the comments in the code for explanation.

The source code has also been attached to this response.

Hope this helps!

Download java
3 0
3 years ago
An experimenter discovers that the time for people to detect a string of letters on a computer screen is 400 milliseconds, and t
nadya68 [22]

Answer:

The correct answer to the following question will be Option D (Subtractive method ).

Explanation:

  • This approach essentially requests a participant to construct two activities that are already in almost every way similar, except for a mental process that is assumed to also be included in any of the activities although omitted in another.
  • This method will be much more valuable when deciding the period for phonemic awareness, despite text-string identification.

The other three options are not related to the given scenario. So that Option D is the right answer.

3 0
3 years ago
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