<span><span>Lets first solve the first one:</span></span>
<span><span>log<span>(x+9)</span></span>=<span>log<span>(2x−7)</span></span></span>
Convert the logarithmic equation to an exponential equation.
<span><span>10^<span>log<span>(x+9)</span></span></span>=<span>10^<span>log<span>(2x−7)</span></span></span></span>
Remember that <span><span>10^<span>logx</span></span>=x</span>, so
<span>x+9=2x−7</span>
Move values with 'x' to the right hand side.
<span>7+9=2x-x</span>
Combine like terms.
<span>16=x so,</span>
<span>x=16</span>
Check:
<span><span>log<span>(x+9)</span></span>=<span>log<span>(2x−7)</span></span></span>
If <span>x=16</span>
<span><span>log<span>(16+9)</span></span>=<span>log<span>(2<span>(16)</span>−7)</span></span></span>
<span><span>log25</span>=<span>log<span>(32−7)</span></span></span>
<span><span>log25</span>=<span>log25</span></span>
<span>x=16</span> is a solution.
Solve the second one like i solved this one, try it
