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Nitella [24]
3 years ago
15

What is 19/25 in a fraction or mixed number?

Mathematics
2 answers:
Luda [366]3 years ago
7 0
I think the answer is still 19/25. I believe that is as far as you can reduce it too.
True [87]3 years ago
6 0
19/25 is already a fraction, and you can't simplify it any more.
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Of the last 18 trains to pull into Castroville Station, 12 were full. Considering this data, how many of the next 12 trains woul
lana66690 [7]

Answer:8

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Shortly after creating a car washing business, you made $65 washing ten
nevsk [136]

Answer:

A) For the slope;

Rate of change in profit per change in number of cars washed = 10

B) when he had not washed any car, he was in debt of of $35

C) When he made $255, he had washed 29 cars

Step-by-step explanation:

Slope intercept equation of a line is;

y = mx + c

you made $65 washing ten

cars. Thus, x = 10 and y = 65

So, 65 = 10m + c - - - - (eq 1)

Then after fifteen cars, you made $115.

Thus, x = 15 and y = 115

So; 115 = 15m + c - - - - (eq 2)

Subtract equation 1 from eq(2) to get;

115 - 65 = 15m - 10m + c - c

50 = 5m

m = 50/5

m = 10

Putting 10 for m in eq 1 gives;

65 = 10(10) + c

65 = 100 + c

c = 65 - 100

c = -35

A) Since the slope is m = 10 and slope is m = Δy/Δx, it means that;

Rate of change in profit per change in number of cars washed = 10

B) c = -35 is the y-intercept.

This means when x = 0, y = - 35.

It implies that when he had not washed any car, he was in debt of of $35

C) since we have the slope and intercept, equation is;

y = 10x - 35

If he has made $255,then we have;

255 = 10x - 35

255 + 35 = 10x

290 = 10x

x = 290/10

x = 29 cars washed.

7 0
3 years ago
Which special case is represented by?
vladimir1956 [14]

Answer:

A. the difference of two squares

Step-by-step explanation:

we are given

x^2-121

we can write

121=11\times 11

121=11^2

so, we can see that

x^2 is square

11^2 is also square

so,

x^2-11^2=square-square

It means that

two squares are subtracted

so, it is difference of two squares

so,

A. the difference of two squares

3 0
3 years ago
Divide 3x^3 - 2x^2 - 61x - 20 by x - 5.
jek_recluse [69]

Answer:

3x² + 13x + 4

Step-by-step explanation:

3x³ - 2x² - 61x - 20

3x³ - 15x² + 13x² - 65x + 4x - 20

[3x²(x - 5) + 13x(x - 5) + 4(x - 5)]/(x-5)

3x² + 13x + 4

8 0
3 years ago
he owner of a local supermarket wants to estimate the difference between the average number of gallons of milk sold per day on w
stellarik [79]

Answer:

90% confidence interval is ( -149.114, -62.666   )

Step-by-step explanation:

Given the data in the question;

Sample 1                                Sample 2

x"₁ = 259.23                            x"₂ = 365.12

s₁  = 34.713                              s₂ = 48.297

n₁ = 5                                       n₂ = 10

With 90% confidence interval for μ₁ - μ₂ { using equal variance assumption }

significance level ∝ = 1 - 90% = 1 - 0.90 = 0.1

Since we are to assume that variance are equal and they are know, we will use pooled variance;

Degree of freedom DF = n₁ + n₂ - 2 = 5 + 10 - 2 = 13

Now, pooled estimate of variance will be;

S_p^2 = [ ( n₁ - 1 )s₁² + ( n₂ - 1)s₂² ] / [ ( n₁ - 1 ) + ( n₂ - 1 ) ]

we substitute

S_p^2 = [ ( 5 - 1 )(34.713)² + ( 10 - 1)(48.297)² ] / [ ( 5 - 1 ) + ( 10 - 1 ) ]

S_p^2 = [ ( 4 × 1204.9923) + ( 9 × 2332.6 ) ] / [  4 + 9 ]

S_p^2 = [ 4819.9692 + 20993.4 ] / [  13 ]

S_p^2 = 25813.3692 / 13

S_p^2 = 1985.64378

Now the Standard Error will be;

S_{x1-x2 = √[ ( S_p^2 / n₁ ) + ( S_p^2 / n₂ ) ]

we substitute

S_{x1-x2 = √[ ( 1985.64378 / 5 ) + ( 1985.64378 / 10 ) ]

S_{x1-x2 = √[ 397.128756 + 198.564378 ]

S_{x1-x2 = √595.693134

S_{x1-x2 = 24.4068

Critical Value = t_{\frac{\alpha }{2}, df = t_{0.05, df=13 = 1.771  { t-table }

So,

Margin of Error E =  t_{\frac{\alpha }{2}, df × [ ( S_p^2 / n₁ ) + ( S_p^2 / n₂ ) ]

we substitute

Margin of Error E = 1.771 × 24.4068

Margin of Error E = 43.224

Point Estimate = x₁ - x₂ = 259.23 - 365.12 = -105.89

So, Limits of 90% CI will be; x₁ - x₂ ± E

Lower Limit = x₁ - x₂ - E = -105.89 - 43.224 = -149.114

Upper Limit = x₁ - x₂ - E = -105.89 + 43.224 = -62.666

Therefore, 90% confidence interval is ( -149.114, -62.666   )

3 0
3 years ago
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