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3 years ago

What is 19/25 in a fraction or mixed number?

Mathematics

2 answers:

Luda [366]3 years ago

7 0

I think the answer is still 19/25. I believe that is as far as you can reduce it too.

True [87]3 years ago

6 0

19/25 is already a fraction, and you can't simplify it any more.

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A shipment of sugar fills 2 2/3 containers. if each container holds 2 1/7 tons of sugar, what is the amount of sugar in the tire

maks197457 [2]

The shipment is 5 5/7 tons

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4 years ago

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99 Points!

patriot [66]

Simple...

you have:

1.) Find the slope of the line using (-2,1) and (3,6)

Using $\frac{ y_{1}- y_{2} }{ x_{1} - x_{2} }$

$\frac{1-6}{-2-3} = \frac{-5}{-5}$

m=1 (slope)

2.)Tell whether the equation, 8y+3=5x+3, is a direct variation.

y= $\frac{5x}{8}$ (None)

3.)What is the slope and y-intercept of the graph of the equation y=2x+3?

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Thus, your answer.

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3 years ago

Evaluate: b − a for a = 2 and b = 7

zmey [24]

Answer:

Step-by-step explanation:

b − a

Let a = 2 and b = 7

7-2

7 0

4 years ago

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Let f be the function defined as follows:1. If a = 2 and b = 3, is f continuous at x = 1? Justify your answer.2. Find a relation

Arada [10]

Answer:

1. not continuous, as the function definitions deliver different function values at x=1 when approaching this x from the left and from the right side.

2 = a + b

0 = 2a + b

a = -2

b = 4

Step-by-step explanation:

the function is continuous at a specific point or value of x, if the f(x) = y functional value is the same coming from the left and the right side at that point.

1. that means that for x=1

3 - x = ax² + bx

so,

3 - 1 = a×1² + b×1 = a + b

2 = a + b

we have to use a=2 and b=3

2 = 2 + 3 = 5

2 is not equal 5, so the assumed equality is false, so the function is not continuous there.

2. point 1 gave us already the working relationship between a and b.

2 = a + b

only if that is true, is the function continuous at x=1.

3. now for x=2

5x - 10 = ax² + bx

5×2 - 10 = a×2² + b×2 = 4a + 2b

10 - 10 = 4a + 2b

0 = 4a + 2b

0 = 2a + b

4. to find a and b to be continuous at both locations x=1 and x=2 both expressions in a and b must apply.

so, they establish a system of 2 equations with 2 variables.

2 = a + b

0 = 2a + b

a = 2 - b

0 = 2×(2-b) + b = 4 - 2b + b = 4 - b

b = 4

therefore

a = 2 - 4 = -2

5. I cannot draw a graph here.

just use now the function

3 - x, x < 1

‐2x² +4x, 1 <= x < 2

5x - 10, x >= 2

8 0

3 years ago

PLEASE help me...! I am really stuck on this question.

Mashcka [7]

Answer:

Step-by-step explanation:

the domain of 3^x is (-∞,∞) and the range is (0,∞)

the domain of 3^x-5 is (-∞,∞) and the range is (-5,∞)

the domain doesn't change, the range (-5,∞)

8 0

3 years ago