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Alekssandra [29.7K]
3 years ago
10

If A has the coordinate -10 and C has the coordinate 14 and B is the midpoint of a AC, then what is the coordinates of D which i

s the midpoint of BC?
Mathematics
1 answer:
salantis [7]3 years ago
5 0

Answer:

  8

Step-by-step explanation:

The midpoint of AC is ...

  B = (A +C)/2 = (-10 +14)/2 = 2

The midpoint of BC is ...

  D = (B +C)/2 = (2 +14)/2 = 8

The midpoint of BC is 8.

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4) Find the m<5, m<7, and the m<6 in the diagram below.
bazaltina [42]

Answer:

45,12,11

Step-by-step explanation:

voa respectively

8 0
3 years ago
I need help fast please!!
kaheart [24]

Solution set is: (7,\frac{13}{3})

Option B is correct

Step-by-step explanation:

We need to find the solution to system of equations

y=\frac{1}{3}x+2\\y=\frac{4}{3}x-5

Let:

y=\frac{1}{3}x+2\,\,\,eq(1)\\y=\frac{4}{3}x-5\,\,\,eq(2)

Putting value of y from eq(2) into eq(1)

\frac{4}{3}x-5=\frac{1}{3}x+2\\Combining\,\,like\,\,terms:\\\frac{4}{3}x-\frac{1}{3}x=2+5\\Taking\,\,LCM\\\frac{4x-1x}{3}=7\\\frac{3x}{3}=7\\x=7

So, value of x=7

Putting value of x into equation 1 to find the value of y:

y=\frac{1}{3}x+2\\y=\frac{1}{3}(7)+2\\y=\frac{7}{3}+2\\Taking\,\,LCM\\y=\frac{7+2*3}{3}\\y=\frac{7+6}{3}\\y=\frac{13}{3}

So, value of y = \frac{13}{3}

Solution set is: (7,\frac{13}{3})

Option B is correct

Keywords: System of equations

Learn more about system of equations at:

  • brainly.com/question/9045597
  • brainly.com/question/3739260
  • brainly.com/question/13168205

#learnwithBrainly

3 0
4 years ago
I need help I don’t know how to do this
Law Incorporation [45]

Answer:

its about checkers cou nt and answer

Step-by-step explanation:

5 0
3 years ago
F(x) = -x² – 10x + 16<br> Find f(-7)
Gala2k [10]

Answer:

-5

Step-by-step explanation:

or, f(x) = -x^2+10x+16

or, f(7) = (-7)^2+10*-7+16 (-7*-7=49)

=49-70+16

=65-70

=-5

5 0
3 years ago
2 Points<br> Which of the following is(are) the solution(s) to . x+6 = 2x - 1?
seropon [69]

Answer:

x = 7

Step by step explanation:

<em>minus</em><em> </em><em>x</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em>

6 = x -1

<em>add</em><em> </em><em>1</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em>

<em>x</em><em> </em><em>=</em><em> </em><em>7</em>

7 0
3 years ago
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