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chubhunter [2.5K]
3 years ago
15

A solution at 25 degrees Celsius has a pH of 4.48. What is the pOH of this solution?

Chemistry
2 answers:
AlexFokin [52]3 years ago
7 0

Answer:

9.52

Explanation:

I just took the test ;)

just olya [345]3 years ago
4 0

Hello :)

I just took the quiz, so let me give you a step-by-step explanation of how I solved the problem. Disregard the 25 degrees, it is not needed to find the answer

pH + pOH = 14

4.48 (4.48 is the given pH in problem) + pOH = 14

4.48-4.48 + pOH = 14-4.48 (subtract 4.48 from 14)

pOH = 9.52 (letter c)

Hope this helped :)

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Quantum transitions that result in the characteristic sharp lines of the X-ray spectrum always involve
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Answer: 5

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4 0
3 years ago
Describe how particles of iron (Fe) an oxygen (O2) react to how produce oxide (Fe2O3), also known as rust.
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Answer:

Described by a redox reaction below

Explanation:

Iron(III) oxide is an ionic compound, since it consists of a metal, iron, and a nonmetal, oxygen.

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As a result, positive ions (cations) and negative ions (anions) are formed. When iron reacts with oxygen, the following reaction takes place:

4 Fe (s) + 3 O_2 (g)\rightarrow 2 Fe_2O_3 (s)

This is a redox (oxidation–reduction) reaction, since we have electron loss and gain. Four iron atoms lose a total of 12 electrons to obtain a +3 charge in the final compound, while 3 oxygen molecules gain these 12 electrons to become 6 oxide anions with a -2 charge.

4 0
3 years ago
PLS HELP Students in a chemistry class added 5 g of Zinc (Zn) to 50 g of hydrochloric acid (HCl). A chemical reaction occurred t
Vitek1552 [10]

Answer: In simplest case mass of reactants is same as mass of products.

Without thinking this question deeper, mass of ZnCl2 would be 49, but..

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of Hydrogen Chloride is 50 g / 36.458 g/mol = 1,371 mol.

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So it is possible to produce only 0.076476 mol Hydrogen and its mass

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3 years ago
Which two elements are most abundant within the sun?
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We can also perform a similar calculation for the mass defect and binding energy for nuclear reactions using the masses of the a
sukhopar [10]

Answer:

See Explanation

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\frac{235}{92} U + \frac{1}{0} n ---->\frac{137}{52} Te + \frac{97}{40} Zr +2\frac{1}{0} n

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[235.04393 + 1.00867] - [ 136.92532 + 96.91095 + 2(1.00867)]

=  236.0526 - 235.85361

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ii) \frac{10}{5}B + \frac{1}{0}n-----> \frac{7}{3} Li + \frac{4}{2} He + Energy

Hence the mass defect is;

[10.01294 + 1.00867] - [7.01600 + 4.00260]

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0.00301 amu = 0.00301 * 1.66 * 10^-27 = 4.997 * 10^-30 Kg

Binding energy = Δmc^2

Binding energy = 4.997 * 10^-30 Kg * (3 * 10^8)^2 = 4.5 * 10^-13 J

7 0
3 years ago
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