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Over [174]
3 years ago
12

How many times more acidic is a solution with a pH of 2 than one with a pH of 4?

Chemistry
1 answer:
Law Incorporation [45]3 years ago
5 0

Answer: 100 times more acidic

Explanation: idek :/

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Why does the ice melt when you hold it in your hand? A.Heat is transferred from your hand to the ice cube. B.Heat from the ice c
Thepotemich [5.8K]
A. Heat is transferred from your hand to the ice cube.
3 0
3 years ago
What has more atoms, a mole of carbon or a mole of fluorine?
GuDViN [60]

Answer:

They have the same number of atoms

Explanation:

The mole (symbol: mol) is the base unit of amount of substance.

Think of mole meaning like inch. An inch of grass is the same as an inch of a flower. Mole is the standard measuring unit of atoms.

6 0
2 years ago
At 400 K, This Reaction Has Kp 8.2 X 104 What Is Kp At 400 K For The Following Reaction
kondor19780726 [428]

The given question is incomplete, here is a complete question.

At 400 K, this Reaction has K_p=8.2\times 10^{-4}

SO_3(g)\rightleftharpoons SO_2(g)+\frac{1}{2}O_2(g)

What Is K_p at 400 K for the following reaction?

2SO_3(g)\rightleftharpoons 2SO_2(g)+O_2(g)

(A) 8.2 x 10⁻⁴

(B) 2.9 x 10⁻²

(C) 6.7 x 10⁻⁷

(D) 1.6 x 10⁻⁷

Answer : The correct option is, (C) 6.7\times 10^{-7}

Explanation :

The given chemical equation follows:

SO_3(g)\rightleftharpoons SO_2(g)+\frac{1}{2}O_2(g)

The equilibrium constant for the above equation, K_p=8.2\times 10^{-4}.

We need to calculate the equilibrium constant for the following equation of above chemical equation, which is:

2SO_3(g)\rightleftharpoons 2SO_2(g)+O_2(g),   K_p'

The equilibrium constant for the doubled reaction will be the square of the initial reaction.

Or, we can say that

If the equation is multiplied by a factor of '2', the equilibrium constant will be the square of the equilibrium constant of initial reaction.

The value of equilibrium constant for the following reaction is:

K_{p}'=(K_p)^2

K_{p}'=(8.2\times 10^{-4})^2

K_{p}'=6.7\times 10^{-7}

Hence, the value of equilibrium constant for the following reaction is, 6.7\times 10^{-7}

7 0
3 years ago
What is the substrate of the enzyme pepsin
8090 [49]

Enzyme Substrate Products

Lipase Lipid Glycerol + Fatty Acid

Enzyme Substrate Products

Pepsin Protein Peptides + Amino Acids

Trypsin Protein Peptides + Amino Acids

6 0
3 years ago
The question is in the photo
Alenkinab [10]

The concentration of LiOH in the reaction is 0.103 M

<h3>What is the concentration of lithium hydroxide?</h3>

This is a neutralization reaction and the equation of the reaction is written as; H2SO4(aq) + 2LiOH(aq) ---->Li2SO4(aq) + H2O(l)

The average volume of acid used is obtained from;

8.54 + 8.51 + 8.68/ 3 = 8.58 mL

CA = 0.150 M

VA = 8.58 mL

CB = ?

VB= 25.0 mL

NA = 1

NB = 2

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CB = CAVANB/VBNA

CB = 0.150 * 8.58 * 2/25.0 * 1

CB = 0.103 M

The concentration of LiOH in the reaction is 0.103 M

Learn more about neutralization reaction:brainly.com/question/20038776

#SPJ1

4 0
2 years ago
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