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aksik [14]
2 years ago
12

Consider a convex hexagon in which all pairs of opposite sides are parallel. Prove that if one pair of opposite sides have equal

length, then the other two pairs of opposite sides also have equal length.
Mathematics
1 answer:
hjlf2 years ago
6 0

A pair of the opposite sides of a hexagon has equal length and this is proved below.

<h3>How to illustrate the hexagon?</h3>

It should be noted that a hexagon is a polygon that has six sides.

In this case, it has 6 sides.

The total angles will be:

= (n - 2) × 180

= (6 - 2) × 180

= 720°

Each angle will hence be:

= 720°/6

= 120°

Each angle are equal and this illustrates that the parallel sides are equal.

A diagram is attached to illustrate the pair of parallel sides.

Learn more about hexagon on:

brainly.com/question/1615720

#SPJ1

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3x+5-x=2x+7 is infinite real soluction, no real soluction or one real soluction
Helga [31]

Answer:

There is no real solution.

Step-by-step explanation:

There is no solution because 5 is not equal to 7.

8 0
3 years ago
Your favorite pizza shop chargers $12 for any pizza plus $0.75 per topping. You have $20 to spend. At most, you can buy a pizza
zysi [14]

Answer:

$15 - $11.50 = $3.50

$3.50 divided by .75 is 4.666

Which means the maximum number of toppings they can get is 4

Step-by-step explanation:

5 0
3 years ago
Simplify (3b^8 b^-2)^3
svet-max [94.6K]

Answer:

  27b^18

Step-by-step explanation:

The applicable rules of exponents are ...

  (ab)^c = (a^c)(b^c)

  (a^b)(a^c) = a^(b+c)

  (a^b)^c = a^(bc)

___

(3b^8·b^-2)^3 = (3b^(8-2))^3 = (3b^6)^3

  = 3^3·b^(6·3)

  = 27b^18

5 0
3 years ago
The function f(h)=m(1/2)^h gives the mass, m, of a radioactive substance remaining after h half-lives. Cobalt-60 has a half-life
goldfiish [28.3K]

Answer:

Third choice:

                f(x)=50(0.877)^{10};13.5mg

Explanation:

<u />

<u>1. Data:</u>

<u />

  • Function:

                f(h)=m(1/2)^h

  • Cobalt-60's half-life: 5.3 years

  • Initial mass of cobalt-60:  50 mg

<u>2. Unknown: </u>

<u />

  • equation for the mass of cobalt-60 remaining after 10 years = ?

  • mass remaining =?

<u>3. Solution</u>

<em>Half-life</em> is the time it takes a sample to  decay to half of its initial amount. It is considered constant. Hence, when one half-life passes, the sample has decayed to 50% of the original amount; when two half-lives pass, the sample has decayed to (1/2)×(1/2) = 1/4 = 25%; when three half-lives have elapsed, the sample has decayed to (1/2)³ = 1/8 = 12.5% of its original amount, and so on.

Then, the amound of a sample remaining is calculated as the original amount times (1/2) raised to the number of half-lives elapsed, which is what the given function,  f(h)=m(1/2)^h models.

You just must substitute the data into the function to get the answer to the question:

            f(x)=50(0.5)^{(10/5.3)}

Where, 50 is the original mass of 50g, 0.5 is equal to 1/2, and 10/5.3 gives the number of half-lives (the number of times that 5.3 years is contained in 10 years).

<u>Simplifying:</u>

f(x)=50(0.5)^{(10/5.3)}=50((0.5)^{(1/5.3})^{10}\approx50(0.877)^{10}

Which corresponds to the third choice of the list.

<u>Computing:</u>

               f(x)\approx50(0.877)^{10}=13.5

Which also corresponds to the third choice.

4 0
3 years ago
Read 2 more answers
Please help me again!
nignag [31]

Answer:

144

Step-by-step explanation:

First subtract 180 from 20% of 180.

180 - (20/100 x 180) = 180-36 = 144

7 0
3 years ago
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