1. C : Mg(CN)2
2. B : N2O5
3. D : Ti(ClO4)3
4. A : Ni(NO3)3
5. D : Cobalt (III) Acetate
6. B : Nickel(II) sulfate
7. C : Dinitrogen Tetrafluoride
8. A : Phosphorus pentachloride<em />
9. C : Metallic <em>(<!> This is the only one I'm not 100% sure of)</em>
10. A : Ionic
11. C : Metallic
12. B : Covalent
CO2 ~ 1 atom
N202 ~ 4 atom
CO ~ 2 atom
H2OS ~ 3 atom
B
Collect the salt water and put it in something where it can boil under fire or any other heat source capable to bring the water to boiling temperature. You can consume the collected water safely , but wait for its temperature to fall, except if you need it to be hot.
Answer:
-8024.832 J
Explanation:
The amount of heat energy lost or released, Q, can be calculated thus;
Q = m × c × ∆T
Where;
Q = amount of heat lost (J)
m = mass of substance (g)
c = specific heat capacity (J/g°C)
∆T = change in temperature (°C)
According to this question,
Q = ?
m = 24.3 g
c of Gold = 0.129 J/g°C
∆T = 20°C - 2580.0°C = -2560°C
Using Q = m × c × ∆T
Q = 24.3 × 0.129 × -2560°C
Q = -8024.832 J
This means that 8024.832 J of energy is lost or released.