Answer:
The methyl group will already be present
Explanation:
You want to make 1-methyl-4-nitrobenzene.
The question is, "Do I start with the methyl group on the ring and then nitrate, or do I start with the nitro group on the ring and then add the methyl group?"
The methyl group is activating and ortho, para directing.
The nitro group is deactivating and meta directing.
You want a para-substituted product, so you choose to nitrate toluene, as in the reaction scheme below.
Answer:
The answer is
<h2>1.74 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
From the question
mass of magnesium = 11.81 g
volume = 6.80 mL
The density of the metal is
We have the final answer as
<h3>1.74 g/mL</h3>
Hope this helps you
Answer:
B is the correct answer!
Explanation:
Balanced equation is Mg(OH)2 + 2 HCl = MgCl2 + 2 H2O
HCl is the limiting reactant because it gives the smaller amount of MgCl2 I did the math. This means you will be left with Mg(OH)2 since HCl completely runs out.
If HCl is the limiting reactant, Mg(OH)
2 is the excess reactant.
Mg(OH)
2 is a base, so the solution will be basic.
C2H6 (g) + O2 (g). --> CO2(g)+H2O (g)
2C2H6 (g) + 7O2 (g). --> 4CO2(g)+6H2O (g)
(8.45 x 10^23)/(6.022x10^23) = 1.403 moles H2O
1.403 moles H2O x (4molCO2/6molH2O)= .935 moles CO2
.935 moles CO2 x (6.022 x10^23)= 5.63 x 10^23 molecules CO2
C. Glacial evidence found in South America
