Answer:
0.42 J/gºC
Explanation:
We'll begin by calculating the heat energy used to heat up the water. This can be obtained as follow:
Mass (M) of water = 560 g
Initial temperature (T₁) = 22.7 °C
Final temperature (T₂) = 80.3 °C.
Specific heat capacity (C) of water = 4.18 J/gºC
Heat (Q) absorbed =?
Q = MC(T₂ – T₁)
Q = 560 × 4.18 (80.3 – 22.7)
Q = 2340.8 × 57.6
Q = 134830.08 J
Finally, we shall determine the specific heat capacity of the burner. This can be obtained as follow:
Mass (M) of burner = 699 g
Initial temperature (T₁) = 482.0°C
Final temperature (T₂) = 22.7 °C
Heat (Q) evolved = – 134830.08 J
Specific heat capacity (C) of the burner =?
Q = MC(T₂ – T₁)
–134830.08 = 699 × C (22.7 – 482.0)
–134830.08 = 699 × C × –459.3
–134830.08 = –321050.7 × C
Divide both side by –321050.7
C = –134830.08 / –321050.7
C = 0.42 J/gºC
Therefore, the specific heat capacity of the burner is 0.42 J/gºC
