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Sliva [168]
2 years ago
6

(b) difference between metalloids and alloys​

Chemistry
2 answers:
Alisiya [41]2 years ago
8 0

Answer:

Metalloid: It is actually any chemical element which have the properties just like the mixture properties of metal and non metal. Or Which contain those properties in between the non metal and metal.Mostly the metalloids have the appearance just like the metallic appearance  And also they are the brittle one's .  Boron and silicon are the example.

Alloy: They are usually the mixture of metals. Some times mixture of metal may contain another element .They are recognized by their metallic bonding characteristics.

Explanation: By combining with other metals metalloid can form the alloy.

blsea [12.9K]2 years ago
5 0

Answer:

<u>Metalloid -</u>

A metalloid is a chemical element with properties intermediate between those of typical metals and nonmetals

<u>Alloy</u> -

An alloy is a mixture of metals or a mixture of a metal and another element. Alloys are defined by a metallic bonding character.

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If 125 ml of o2 gas exerts a pressure of 1.0 atm inside a cylinder, what will the pressure be if the cylinder compressed the vol
Lelu [443]
<h2>Hello!</h2>

The answer is: The new pressure is 1.67 atm.

<h2>Why?</h2>

From the statement, we know that the temperature remains constant and the gas volume is changing, meaning that the new pressure will be different than the first pressure.

Since the temperature remains constant, we can calculate the new pressure using the Boyle's Law.

The Boyle's Law states that:

P_{1}V_{1}=P_{2}V_{2}

Where,  

P is the pressure of the gas.

V is the volume of the gas.

Then, the given information is:

V_{1}=125ml=0.125L\\P_{1}=1atm\\V_{2}=75ml=0.075L

Remember, 1 L is equal to 1000 mL.

So,

125mL*\frac{1L}{1000mL}=\frac{125mL*1L}{1000mL}=0.125L\\\\75mL*\frac{1L}{1000mL}=\frac{75mL*1L}{1000mL}=0.075L

So, calculating the new volume, we have:

P_{1}V_{1}=P_{2}V_{2}\\\\1atm*0.125L=P_{2}*0.075L\\\\P_{2}=\frac{1atm*0.125L}{0.075l}=1.67atm

Hence, the new pressure is 1.67 atm.

Have a nice day!

7 0
2 years ago
How many grams of n2f4 can be produced from 225g f2?
3241004551 [841]
The answer is 615.91 grams of <span>n2f4

Solution:
225g F2 x [(1molF2)/(38gramsF2)] x [</span>(1molF2)/(1molN2F4)] x [(104.02 grams N2F4)/(1molN2F4)]
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8 0
3 years ago
Why boiling point is more when vanderwall force if more?
jek_recluse [69]

Answer:

It is the intermolecular forces acting between the molecules that cause attractions between them making them liquids or solids. The strength of Van der Waals forces depends primarily on the number of electrons in total in the molecule, so larger molecules will have higher boiling points.

Explanation:

6 0
2 years ago
Determine the volume in mL of 0.37 M HClO4(aq) needed to reach the half-equivalence (stoichiometric) point in the titration of 2
Dimas [21]

Answer:

14.3mL you require to reach the half-equivalence point

Explanation:

A strong acid as HClO₄ reacts with a weak base as CH₃CH₂NH₂, thus:

CH₃CH₂NH₂ + HClO₄ → CH₃CH₂NH₃⁺ + ClO₄⁻

As the reaction is 1:1, to reach the equivalence point you require to add the moles of HClO₄ equal to moles CH₃CH₂NH₂ you add originally. Also, half-equivalence point requires to add half-moles of CH₃CH₂NH₂ you add originally.

Initial moles of CH₃CH₂NH₂ are:

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0.0106moles CH₃CH₂NH₂

To reach the half-equivalence point you require:

0.0106moles ÷ 2 = 0.005304 moles HClO₄

As concentration of HClO₄ is 0.37M, volume you require to add 0.005304moles is:

0.005304 moles HClO₄ ₓ (1L / 0.37mol) = 0.0143L =

<h3> 14.3mL you require to reach the half-equivalence point</h3>

7 0
2 years ago
When a chemical reaction creates a thin film outline of an anmial or plant what type of preservation has occured?
klasskru [66]
I believe carbonisation.
4 0
3 years ago
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