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Sliva [168]
3 years ago
6

(b) difference between metalloids and alloys​

Chemistry
2 answers:
Alisiya [41]3 years ago
8 0

Answer:

Metalloid: It is actually any chemical element which have the properties just like the mixture properties of metal and non metal. Or Which contain those properties in between the non metal and metal.Mostly the metalloids have the appearance just like the metallic appearance  And also they are the brittle one's .  Boron and silicon are the example.

Alloy: They are usually the mixture of metals. Some times mixture of metal may contain another element .They are recognized by their metallic bonding characteristics.

Explanation: By combining with other metals metalloid can form the alloy.

blsea [12.9K]3 years ago
5 0

Answer:

<u>Metalloid -</u>

A metalloid is a chemical element with properties intermediate between those of typical metals and nonmetals

<u>Alloy</u> -

An alloy is a mixture of metals or a mixture of a metal and another element. Alloys are defined by a metallic bonding character.

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Answer:

Quick you said:

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3 years ago
The question is in the picture below
Rus_ich [418]

Answer:

\Delta\text{H}_1+2\Delta\text{H}_2-\Delta\text{H}_3

Explanation:

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With Hess's Law in mind, let's see how A can be converted to 2C +E.

\bf{\text{A} \rightarrow 2\text{B}}                  (Δ\text{H}_1)  -----(1)

Since we have 2B, multiply the whole of II. by 2:

\bf{2\text{B} \rightarrow 2\text{C} +2\text{D}}       (2Δ\text{H}_2) -----(2)

This step converts all the B intermediates to 2C +2D. This means that the overall reaction at this stage is \text{A} \rightarrow 2\text{C} +2\text{D}.

Reversing III. gives us a negative enthalpy change as such:

\bf{2\text{D} \rightarrow \text{E}}                  (-Δ\text{H}_3) -----(3)

This step converts all the D intermediates formed from step (2) to E. This results in the overall equation of \text{A} \rightarrow 2\text{C} +\text{E}, which is also the equation of interest.

Adding all three together:

\text{A} \rightarrow 2\text{C}+\text{E}            (\bf{\Delta\text{H}_1+2\Delta\text{H}_2-\Delta\text{H}_3 })

Thus, the first option is the correct answer.

Supplementary:

To learn more about Hess's Law, do check out: brainly.com/question/26491956

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Answer:

When the concentration of all the reactants increases, more molecules or ions interact to form new compounds, and the rate of reaction increases. When the concentration of a reactant decreases, there are fewer of that molecule or ion present, and the rate of reaction decreases.

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