Evaluate the given expression 9P6

Mathematics

1 answer:

iogann1982 [59]3 years ago

8 0

Answer:

60480

Step-by-step explanation:

$nPr=\frac{n!}{\left(n-r\right)!}\\\\nPr=\frac{9!}{\left(9-6\right)!}=nPr=\frac{9!}{\left3\right!}=\frac{9*8*7*6*5*4*3*2*1}{3*2*1}=60480$

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