Question

Evaluate the given expression 9P6

Answer 1

Answer:

60480

Step-by-step explanation:

$nPr=\frac{n!}{\left(n-r\right)!}\\\\nPr=\frac{9!}{\left(9-6\right)!}=nPr=\frac{9!}{\left3\right!}=\frac{9*8*7*6*5*4*3*2*1}{3*2*1}=60480$